Is my Guss is 300 by the fardes I can think of
This is in slope-intercept form, so you can think of it as being y=mx+b. Invert m (the slope) and flip its sign, and then substitute the x and y values in and solve for b. The answer is y=7/2x-20.
Answer:
Never
Never
Never
Step-by-step explanation:
The equations given are
2x1−6x2−4x3 = 6 ....... (1)
−x1+ax2+4x3 = −1 ........(2)
2x1−5x2−2x3 = 9 ..........(3)
the values of a for which the system of linear equations has no solutions
Let first add equation 1 and 2. Also equation 2 and 3. This will result to
X1 + (a X2 - 6X2) - 0 = 5
And
X1 + (aX2-5X2) + 2X3 = 8
Since X2 and X3 can't be cancelled out, we conclude that the value of a is never.
a unique solution,
Let first add equation 1 and 2. Also equation 2 and 3. This will result to
X1 + (a X2 - 6X2) - 0 = 5
And
X1 + (aX2-5X2) + 2X3 = 8
The value of a = never
infinitely many solutions.
Divide equation 1 by 2 we will get
X1 - 3X2 - 2X3 =3
Add the above equation with equation 3. This will result to
3X1 - 8X2 - 4X3 = 12
Everything ought to be the same. Since they're not.
Value of a = never.
Answer: option B. it has the highest y-intercept.
Explanation:
1) point -slope equation of the line
y - y₁ = m (x - x₁)
2) Replace (x₁, y₁) with the point (5,3):
y - 5 = m (x - 3)
3) Expand using distributive property and simplify:
y - 5 = mx - 3m ⇒ y = mx + 5 - 3m
4) Compare with the slope-intercept equation of the line: y = mx + b, where m is the slope and b is the y-intercept
⇒ slope = m
⇒ b = 5 - 3m = y - intercept.
Therefore, for the same point (5,3), the greater m (the slope of the line) the less b (the y-intercept); and the smaller m (the slope) the greater the y - intercept.
Then, the conclusion is: the linear function with the smallest slope has the highest y-intercept (option B).
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