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Artyom0805 [142]

2 years ago

7

Kennedy saves $5.50 for each hour she works. She need to save an additional $44 to buy an E-reader. How many more hours does Ken

nedy need to work to pay for the E-reader?

1 answer:

Shalnov [3]2 years ago

6 0

The answer tou your question is 8 more hours

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Angelica calculated the distance between the two points shown on the graph below. (1st picture)

Alex Ar [27]

Use the distance formula to find the value of the side lengths.
d=√((x1-x2)²+(y1-y2)²

d of side AC is 6

d of side CB is 10

Angela's use of the Pythagorean Theorem of 10²+6²+c² is incorrect; she put the right values in the wrong spots, the formula needed is:
6²+10²=c²

Option C- Angelica's side lengths were too long.

7 0

2 years ago

Read 2 more answers

A box contains 4 black shirts, 8 blue shirts, 4 black pants, and 10 blue pants. Determine the probability of randomly selecting

Elenna [48]

So there is 26 shirts in total because 4+8+4+10=26 Then you need to take 26-4=22. You do this because there is 26 total clothing and only 4 of them aren't either a blue piece of clothing or pants that means you have 22 pieces of clothing that are blue or pants. So your odds of picking a blue piece of clothing or pants is 22/26.

Hope this Helps!!

3 0

3 years ago

Is the function linear or quadratic?

fgiga [73]

It is quadratic since a quadratic function is of the form :y=ax²+bx+c ,a,b,c are constants.

7 0

3 years ago

Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%

Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

$\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }$

Note that

$\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}$

When dividing $\sqrt[7]{x^5}$ by $\sqrt[4]{x^2},$ we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

$\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}$

and the result is $x^{\frac{3}{14}}=\sqrt[14]{x^3}$

2. Given equation $3\sqrt[4]{(x-2)^3} -4=20$

Add 4:

$3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24$

Divide by 3:

$\sqrt[4]{(x-2)^3} =8$

Rewrite the equation as:

$(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3$

Hence,

$\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18$

3 0

2 years ago

Order the numbers 21 , 40, and 42 from least to greatest based on how many numbers are in their prime factorization.

lora16 [44]

Answer:

21,40,42

Step-by-step explanation:

That's it.Wish it's correct.:D

6 0

2 years ago