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erik [133]
3 years ago
8

A jeweler had a fixed amount of gold to make bracelets and necklaces. The amount of gold in each bracelet is 6 grams and the amo

unt of gold in each necklace is 18 grams. The jeweler used 168 grams of gold and made 4 more necklaces than bracelets. Determine the number of bracelets made and the number of necklaces made.
Mathematics
1 answer:
blagie [28]3 years ago
4 0

Number of bracelets made is 4 and number of necklace made is 8

<em><u>Solution:</u></em>

Let "b" be the number of bracelets made

Let "n" be the number of necklace made

amount of gold in 1 bracelet = 6 grams

amount of gold in 1 necklace = 18 grams

<u><em>Given that he made 4 more necklaces than bracelets</em></u>

number of necklace made = 4 + number of bracelets made

n = 4 + b -------- eqn 1

<em><u>The jeweler used 168 grams of gold</u></em>

Therefore, we can frame a equation as:

number of bracelets made x amount of gold in 1 bracelet + number of necklace made x amount of gold in 1 necklace = 168

b \times 6 + n \times 18 = 168

6b + 18n = 168 ---------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 1 in eqn 2

6b + 18(4 + b) = 168

6b + 72 + 18b = 168

24b = 168 - 72

24b = 96

b = 4

From eqn 1,

n = 4 + b

n = 4 + 4

n = 8

Thus number of bracelets made is 4 and number of necklace made is 8

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