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3 years ago

∠A and ∠ B are supplementary. If m ∠A = 117°, what is the measure of ∠B?

Mathematics

2 answers:

Dimas [21]3 years ago

8 0

63 degrees because 180-117 is 63.

Yakvenalex [24]3 years ago

7 0

Supplementary=Add up to 180.
<A+<B=180
117+x=180
180-117=63
63=<B

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kherson [118]

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3 years ago

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How do you solve 7a- 17=4a+1

Dennis_Churaev [7]

Answer:

a = 6

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3 years ago

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sergejj [24]

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2 years ago

Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea

lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

$\int\limits^y_0 {kx^{2} } \, =1$

where y=23

Clearing k=0.00025

a) $Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5$

b) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2} =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6$

c) The function is equal to:

f(x)=k(1+2x)

$\int\limits^y_0 {k(1+2x)} \, =1$

where y=20

k=0.0024

$Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3$

d) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2} =198.4-176.89=21.51$

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4 years ago

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djverab [1.8K]

Answer:

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3 years ago