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4 years ago

Find the real zeros x^4-40x^2+144=0

Mathematics

1 answer:

IRISSAK [1]4 years ago

4 0

Answer:

the first choice 2 ; -2 ; 6 :-6

Step-by-step explanation:

1) method : you can put this values 2 ; -2 ; 6 :-6 you are 0

2) method you can solve this equation

x^4-40x^2+144=0

let : x² = t and t ≥ 0

t² -40t +144 = 0

Δ = b²- 4ac a= 1 b = - 40 c = 144

Δ =(-40)²- 4(1)(144= 1600 -576 = 1024=32²

t1 = (40+32)/2 = 36 = 6²

t1 = (40-32)/2 = 4 = 2²

but : x² = t and t ≥ 0

1)case : x² = 6² x = 6 or x= -6

2() case : x² =2² x = 2 or x= -2

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