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serg [7]
3 years ago
15

a trinalge has two sides of lengths 4 and 7. what value could the length of the third side be? check all that apply A.9 B.11 C.1

7 D.3 E.5 F.7
Mathematics
1 answer:
hram777 [196]3 years ago
7 0

the answer would be f. 7 because two sides of the triangle are the same

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F(x)=2x^2-x-6 g(x)=4-x (f+g)(x)
Semenov [28]

\large  \boxed{(f + g)(x) = f(x) + g(x)}

The property above is distribution property where we distribute x-term in the function.

Substitute both f(x) and g(x) in.

\large{ \begin{cases} f(x) = 2 {x}^{2}   -  x - 6 \\ g(x) =  4 - x \end{cases}}  \\  \large{f(x) + g(x) = (2 {x}^{2}  - x - 6) + (4 - x)} \\  \large{f(x) + g(x) = 2 {x}^{2}  - x - 6 + 4 - x}

Évaluate/Combine like terms.

\large{f(x)  + g(x) = 2 {x}^{2}  - 2x - 2}

The function can be factored so there are two answers. (Both of them work as one of them is factored form while the other one is not.)

\large{(f + g)(x) = 2 {x}^{2}  -2x -2}

<u>Alternative</u>

\large{(f + g)(x) = 2({x}^{2}  -x - 1)}

<u>Answer</u>

  • (f+g)(x) = 2x²-2x-2
  • (f+g)(x) = 2(x²-x-1)

Both answers work. The second answer is in factored form.

Let me know if you have any doubts!

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mrs_skeptik [129]

Answer:

No.

Step-by-step explanation:

They are not equivalent ratios because they are not multiples or dividends.

Hope this helps...have a nice day <3

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Step-by-step explanation:

HERE,

\angle{PQR=20+2x  } ⠀

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we know that,

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\tt{20+2x+6x=180  } ⠀

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\tt{8x=180-20  } ⠀

\tt{8x=160  } ⠀

\tt{x=\dfrac{160}{20}  } ⠀

\tt{ x=20 } ⠀

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Answer:

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Step-by-step explanation:

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