Using a system of equations, it is found that Peter had $48 at first.
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are:
- Variable x: Peter's money.
- Variable y: Henry's money.
The ratio of peters money to henrys money is 4 : 3, hence:
After Peter spent $12, they had the same amount, hence:
y = x - 12.
Then, replacing in the ratio:
4(x - 12) = 3x
x = 48.
More can be learned about a system of equations at brainly.com/question/24342899
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Answer:
mAB = 49
mABC = 253
mBAC= 156
mACB = 311
Step-by-step explanation:
The answer is B
(3^4*abc^-7)^6=(3^4*6)(a^6)(b^6)(c^6*-7)=(3^24*a^6*b^6)/(b^42)
Answer:
After 5 months the cost of the two phones and monthly service be the same.
Step-by-step explanation:
1st service cost = $50 + $40x, where "x" represents the number of months
2nd service cost = $50x
Now we have to find the number of months the cost of the two phones and monthly service be the same.
Now we have to equivate and find the value of x.
50x = 50 + 40x
Subtracting 40x from both sides, we get
50x - 40x = 50 + 40x - 40x
10x = 50
Dividing both sides by 10, we get
x = 50/10
x = 5
After 5 months the cost of the two phones and monthly service be the same.
Hope you will understand the concept.
Thank you.
10,000,000+2,000,000+400,000+30,000
