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Sav [38]
4 years ago
13

This is an essay don't make it to long but please help its science

Physics
2 answers:
lawyer [7]4 years ago
8 0
In astronomy circumpolar constellations are those ones which never set from viewer's perspective like ursa minor, cassiopiea etc.

Because of the rotation of the Earth and its orbit around the Sun, we divide the stars and constellations into two groups. Some stars and constellations never rise nor set, and they are called circumpolar. All the rest are divided into seasonal stars and constellations. Which stars and constellations will be circumpolar and which seasonal depends on your latitude. 
IgorLugansk [536]4 years ago
5 0

Answer:

This is because of the different latitudes and the movement of the stars.

Explanation:

Some constellations can be seen throughout the year and others only at certain times. In addition to the appearance of the night sky changing throughout the year, it also depends on latitude, that is, the appearance of the sky at the same time is different at different latitudes. For example, you can see the Polar star in the northern hemisphere but you cannot see it in the southern hemisphere. Cruzeiro do Sul, seen in the southern hemisphere, is only seen in the northern hemisphere, close to the horizon, in the tropical region.

Another important difference between the two hemispheres is in the movement we observe for the stars over the course of a night as they revolve around the north celestial pole (in the northern hemisphere) clockwise and around the south celestial pole (in the southern hemisphere) in anticlockwise.

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How does tightening a string on a guitar affect its natural frequency?
iragen [17]
By tightening a string you are actually putting more stress on the string you are giving it a new frequency that isn't natural.

Hope this helps
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3 0
4 years ago
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Who can do my worksheet for me
timurjin [86]

Answer:

what  is it on? like name one of the questions

Explanation:

5 0
3 years ago
The lawn sprinkler consists of four arms that rotate in the horizontal plane. The diameter of each nozzle is 8 mm, and the water
sashaice [31]

Answer: the constant angular velocity of the arms is 86.1883 rad/sec

Explanation:

First we calculate the linear velocity of the single sprinkler;

Area of the nozzle = π/4 × d²

given that d = 8mm = 8 × 10⁻³

Area of the nozzle = π/4 × (8 × 10⁻³)²

A = 5.024 × 10⁻⁵ m²

Now total discharge is dived into 4 jets so discharge for single jet will be;

Q_single = Q / n = 0.006 / 4 = 1.5 × 10⁻³ m³/sec

So using continuity equation ;

Q_single = A × V_single

V_single = Q_single/A

we substitute

V_single = (1.5 × 10⁻³) / (5.024 × 10⁻⁵)

V_single = 29.8566 m/s

Now resolving the forces as shown in the second image,

Vt = Vcos30°

Vt = 29.8566 × cos30°

Vt = 25.8565 m/s

Finally we calculate the angular velocity;

Vt = rω

ω_single = Vt / r

from the given diagram, radius is 300mm = 0.3m

so we substitute

ω_single = 25.8565 / 0.3

ω_single = 86.1883 rad/sec

Therefore the constant angular velocity of the arms is 86.1883 rad/sec

7 0
3 years ago
An arrow is shot vertically upward at a rate of 250ft/s. Use the projectile formula h=−16t2+v0t to determine at what time(s), in
SIZIF [17.4K]

Answer:

The arrow is at a height of 500 feet at time t = 2.35 seconds.

Explanation:

It is given that,

An arrow is shot vertically upward at a rate of 250 ft/s, v₀ = 250 ft/s

The projectile formula is given by :

h=-16t^2+v_ot

We need to find the time(s), in seconds, the arrow is at a height of 500 ft. So,

-16t^2+250t=500

On solving the above quadratic equation, we get the value of t as, t = 2.35 seconds

So, the arrow is at a height of 500 feet at time t = 2.35 seconds. Hence, this is the required solution.

6 0
4 years ago
Read 2 more answers
An observer that moves with an electrical charge senses:
Shtirlitz [24]

Here observer is moving along with an electrical charge

now magnetic field on a moving charge is given by equation

F = qvB sin\theta

electrical force on a moving charge is given by formula

F = qE

so here we can say when observer is moving with the charge it will have two forces on it

1. magnetic force due to existing magnetic field

2. electric force due to electric field

so here he must have to experience both type of field presence

So here correct answer must be

<em>C- electric and magnetic fields </em>

3 0
4 years ago
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