When it has rained for 20 minutes
Answer:
A-18500J
B-232.5 rad/s
Explanation:
A- As the cylinder rotates through 1000rad, it sweeps a distance of
So the work, which is distance times force, of the tension done on the cylinder through that distance is
W = Td = 50 * 370 = 18500 J[/tex]
B- The torque that exerts on the cylinder by the tension is
To = TR = 50*0.37 = 18.5 Nm
As the cylinder is hollow, its moments of inertia is
The torque is generating an angular acceleration of:
The time it takes to go from rest to 1000 rad
Therefore the final rotational speed is
Let's rewrite Hook's law:
where
F is the force
k is the spring's constant
x is the compression/elongation of the spring
Neglecting the sign (since we are not interested in the direction of the force), we can re-arrange the formula and use the data of the problem to find the spring constant:
Therefore, the correct answer is B) 2 N/cm.
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