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lidiya [134]
4 years ago
6

The actions of an employee are not attributable to the employer if the employer has not directly or indirectly encouraged the em

ployee to violate a law and if:

Physics
1 answer:
zepelin [54]4 years ago
4 0

Answer:    the answer is d

Explanation: there are not more than 10 violations  within a twelve month period hope this helps

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In an experiment, the 1 kg cart collides with a 3 kg cart but doesn’t stick to it. Instead, the 3 kg cart gets knock forward by
notka56 [123]

Explanation:

Given that,

Mass of the cart, m_1=1\ kg

Mass of the cart 2, m_2=3\ kg            

Final speed of cart 2, v_2=0.3\ m/s

Final speed of cart 1 is 0 as it comes to rest.

Let us assume that the initial velocity of the cart 2 is 0. So using the conservation of linear momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\m_1u_1+0=0+m_2v_2\\\\m_1u_1=m_2v_2\\\\u_1=\dfrac{m_2v_2}{m_1}\\\\u_1=\dfrac{3\times 0.3}{1}\\\\u_1=0.9\ m/s

So, the initial velocity of the 1.0-kg cart is 0.9 m/s.      

8 0
3 years ago
A light spring with force constant 3.80 n/m is compressed by 7.20 cm as it is held between a 0.300-kg block on the left and a 0.
jeka94
Some dogs may inherit a susceptibility to epilepsy.
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4 years ago
When scientists publish experimental results their results are often criticized by other scientists how is this process a source
stiv31 [10]

Answer: It encourages scientists to give convincing evidence for the results

5 0
3 years ago
If it requires 7.0 JJ of work to stretch a particular spring by 1.7 cmcm from its equilibrium length, how much more work will be
Lynna [10]

Answer:

Explanation:

First of all, well calculate the spring constant k

K = 2Ei/x^2

Where Ei = initial work required

x = initial stretch length

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Now work done in stretching it to 5.3cm (1.7 + 3.6) or 0.053m

EF = kx^2/2

48443 × 0.053^2/2 = 68J

Work done in stretching additional 3.6cm is equal to

68J-7J = 61J

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4 years ago
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Answer:

sorry im english

Explanation:

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3 years ago
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