Complete question is The frequency of the fundamental of the guitar string is 320 Hz. At what speed c do waves move along that string? wavelength is 40 cm.
Answer:
128 m/s
Explanation:
In case where fundamental frequency is given, the speed with waves travel along the string can be calculated using the following formula:
v = f (2L) where L is the length of the string (L = λ/2)
⇒v= f λ
f = 320 Hz (given)
λ = 40 cm = 0.40 m
Substitute the values:
⇒ v = 320 Hz × 0.40 m= 128 m/s
By setting off a lot of gas, that can hurt us.
An object's momentum will change if there is a non-zero net external force acting on it. This assertion is true.
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</h3><h3>What is momentum?</h3>
The momentum is defined as the product of mass and the velocity of the body. It is denoted by the letter P. It occurs due to the applied force. Its unit is Kg m/s².
p=mΔV
If there is a change in the velocity there must be a force acting on the object.
If an object is acted on by a non-zero net external force, its momentum will not remain constant. is an accurate statement.
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Hence, option B is correct.
To learn more about the momentum refer to the link;
brainly.com/question/4956182
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Find the electric flux and the disp at t=0.50ns
<span>Given: </span>
<span>Resistor R = 160 Ω </span>
<span>Voltage ε = 22.0 V </span>
<span>Capacitor C = 3.10 pF = 3.10 * 10^-12 F </span>
<span>time t = 0.5 ns = 0.5 * 10^-9 s </span>
<span>ε0 = 8.85 * 10^-12 </span>
<span>Solution: </span>
<span>ELECTRIC FLUX: </span>
<span>Φ = Q/ε0 </span>
<span>we have ε0, we need to find Q the charge </span>
<span>STEP 1: FIND Q </span>
<span>Q = C ε ( 1 - e^(-t/RC) ) </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 1 - e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 1 - 0.365 } </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 0.635 } </span>
<span>Q = 43.31 * 10^-12 C </span>
<span>STEP 2: WE HAVE Q AND ε0 > >>> SOLVE FOR ELECTRIC FLUX >>> </span>
<span>Φ = Q/ε0 </span>
<span>Φ = { 43.31 * 10^-12 C } / { ε0 = 8.85 * 10^-12 } </span>
<span>Φ = 4.8937 = 4.9 V.m </span>
<span>DISPLACEMENT CURRENT </span>
<span>we use the following equation: </span>
<span>I = { ε / R } { e^(-t/RC) } </span>
<span>I = { 22 / 160 } { e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } </span>
<span>I = { 0.1375 } { 0.365 } </span>
<span>I = 0.0502 A = 0.05 A </span>
