Answer:
potential energy = mgh
= 400÷1000 × 10× 4÷100
= 0.4 × 10 × 0.04
=4/10 ×10×4/100
= 4/10 × 4/10
=16/100
= 0.16 joules
m1 (400) stretches 4cm
m1 (100g) stretches 1cm
so, m2(800g) stretches 8 cm
potential energy of m2 = mgh
= 800/1000 ×10×8/100
= 0.8 × 0.8
=8/10 ×8/10
= 64/100
=0.64 joules
Ratio of s1 to s2
16/100 ÷ 64/100
= 1:4 ( answer)
The magnitude of the change in momentum of the block between zero and 4. 0 seconds is
dp=1.6m/s
<h3>What is the magnitude of the change in momentum of the block between zero and 4. 0 seconds?</h3>
Generally, the equation for the kinematics equation is mathematically given as
x=x+ut+0.5at^2
Therefore
1.6=0+0+0.5*a*1^2
a=0.2m/s^2
In conclusion, change in momentum
dP=mv-mu
2.0*0.8-0
dp=1.6m/s
Read more about Force
brainly.com/question/13370981
Answer:
The value 
Explanation:
From the question we are told that
The acceleration due to gravity is a = 2g
The maximum height is h= 39 m
Generally from the kinematic equation
Here u is the velocity of the ball at maximum height before it start falling and the value is 0 m/s
So
<span>One end of a uniform meter stick is placed against a vertical wall. The other end is held by a lightweight cord that makes an angle, theta, with the stick. The coefficient of static friction between the end of the meter stick and the wall is 0.390. A. what is the maximum value...</span>
