Given:
The given statement are:
a. Eight less than the product of seven and x.
b. The sum of six and the product of three and d.
To find:
The expression for the given statements.
Solution:
a.
Product of 7 and x is 7×x = 7x.
Eight less than the product of seven and x is 7x - 8.
Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.
b.
Product of 3 and d is 3×d = 3d.
The sum of six and the product of three and d is 6+3d.
Therefore, the required expression for the statement "The sum of six and the product of three and d" is 6+3d.
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Technician __Shutdown
Taylor, T___4
Rousche, R _ 3
Hurley, H__ 3
Huang, Hu___2
Gupta, ___ 5
The Numbe of samples of 2 possible from the 5 technicians :
We use combination :
nCr = n! ÷ (n-r)!r!
5C2 = 5!(3!)2!
5C2 = (5*4)/2 = 10
POSSIBLE COMBINATIONS :
TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG
Sample means :
TR = (4+3)/2 = 3.5
TH = (4+3)/2 = 3.5
THu = (4+2) = 6/2 = 3
TG = (4 + 5) = 9/2 = 4.5
RH = (3+3) = 6/2 = 3
RHu = (3+2) /2 = 2.5
RG = (3 + 5) = 8/2 = 4
HHu = (3+2) = 2.5
HG = (3+5) = 8/2 = 4
HuG = (2+5) / 2 = 3.5
Mean of sample mean (3.5+3.5+3+4.5+3+2.5+4+2.5+4+3.5) / 10 = 3.4
Population mean :
(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4
Population Mean and mean of sample means are the same.
This distribution should be approximately normal.
Answer:
I would say that the answer is 4/20
2/3x = 46
2x = 46x3
2x= 138
x=138/2
x= 69
