1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inysia [295]
2 years ago
10

Three points of a function are graphed. A coordinate plane with 3 points plotted at (10, 18), (14, 24), and (18, 30). Which stat

ement describes the function through the points? The function is a direct variation function with a constant of variation of 1.5. The function is a direct variation function with a constant of variation of 1.8. The function is linear but is not a direct variation function. The function is not a linear function. WIll MARK BRAINLIEST
Mathematics
2 answers:
jeyben [28]2 years ago
7 0

Answer:

i think its option 2

Step-by-step explanation:

Anit [1.1K]2 years ago
4 0

Answer:

c

Step-by-step explanation:

You might be interested in
N - 9.02 = 3.87<br> what is (n)?
Nadya [2.5K]

Answer:

n = 12.89

Step-by-step explanation:

Add 9.02 + 3.87

7 0
3 years ago
A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet
Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

L_{1} = 2W_{1}

Also, the area of the walkway of 2 feet wide is 448:

W_{2} = 2 ft

A_{T} = W_{2}*L_{2} = 448 ft^{2}

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

A_{T} = A_{1} + A_{w}    (1)          

The area of the pool is given by:

A_{1} = L_{1}*W_{1}        

A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}  (2)          

And the area of the walkway is:

A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}    (3)          

Where the length of the bigger rectangle is related to the lower rectangle as follows:                  

L_{2} = 4 + L_{1} = 4 + 2W_{1}   (4)        

By entering equations (4), (3), and (2) into equation (1) we have:

A_{T} = A_{1} + A_{w}

A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}                

448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}            

224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}

224 = W_{1}^{2} + 8 + 6W_{1}

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

L_{1} = 2W_{1} = 2*12 ft = 24 ft

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!                                                                                          

8 0
2 years ago
Instructions: Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
GuDViN [60]

Answer:

A) 6

B)5

C)4

D)3

E)1.76

F)1.52

G)1.5

H)1.4

I)1/6

J)2/3

props to the first guy that said it

6 0
3 years ago
Read 2 more answers
X-y=1 <br> PLEASE HELP IM ON A TIME LIMIT
jekas [21]

Answer:

x = 3

y = 2

Step-by-step explanation:

8 0
3 years ago
The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c
Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 \rm{in^3}

Step-by-step explanation:

The linearization or linear approximation of a function f(x) is given by:

f(x_0+dx) \approx f(x_0) + df(x)|_{x_0} where df is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh

Taking R_0=1.5 inches and h=3 inches and evaluating the partial derivatives we obtain:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh

substituting the values and taking dx=0.1 and dh=0.3 inches we have:

V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3}  + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}

Therefore the change in volume is estimated to be 17.20 \rm{in^3}

4 0
3 years ago
Other questions:
  • In circle D, mCAB  32 . Which of the following is the measure of AC ?<br>Equal to 32
    13·1 answer
  • Select the correct answer.<br> If 25% of a number is 100, what is the number?
    10·1 answer
  • What plus what equals 90
    13·2 answers
  • 5x - 2 = 8 + 5y<br> Solve for y and show work.
    10·1 answer
  • What happens to the volume of a rectangular prism when each of the dimensions is doubled
    7·1 answer
  • Simplify numbers with units 1.<br> ​
    13·1 answer
  • Find the area of the shape shown below.
    14·1 answer
  • Question 9
    15·1 answer
  • I need help if you can help me I would really appreciate it
    13·2 answers
  • Circle the exponent <br><br> Help please !!
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!