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inysia [295]
3 years ago
10

Three points of a function are graphed. A coordinate plane with 3 points plotted at (10, 18), (14, 24), and (18, 30). Which stat

ement describes the function through the points? The function is a direct variation function with a constant of variation of 1.5. The function is a direct variation function with a constant of variation of 1.8. The function is linear but is not a direct variation function. The function is not a linear function. WIll MARK BRAINLIEST
Mathematics
2 answers:
jeyben [28]3 years ago
7 0

Answer:

i think its option 2

Step-by-step explanation:

Anit [1.1K]3 years ago
4 0

Answer:

c

Step-by-step explanation:

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Can somebody help me with this question
Alexus [3.1K]
We start with:

y=2x-15
y=5x

Now, we have a perfectly set-up variable we can get rid of: <em>y.</em>

But we need to make either the top or bottom equation negative, so for simplicity, let's make the bottom one negative.

y=2x-15
(-y)=(-5x)

Now simplify.

-3x-15=0

Add 3x on both sides.

3x=15

Divide by 3 on both sides.

x=5



3 0
3 years ago
Read 2 more answers
A racing car used 255 litres of fuel to complete a 340 km race.
kicyunya [14]
255 l ------ 340km
x l -------- 100km

100*255=340x
25500=340x

x=75 litres 
5 0
3 years ago
The price of apples went from $1.99 per lb to $3.19 per lb in four years. Find the rate of change of the price of apples.
navik [9.2K]
3.19 - 1.99 = 1.20 increase in 4 years

1.20/4 = 0.30

rate of change is 0.30 per year  (30 cents per year)
3 0
4 years ago
Read 2 more answers
Please help me!! its sooo hard!!!!
den301095 [7]
Add the length width and height all together
3 0
3 years ago
Read 2 more answers
Solve: x^+4/x-1 = 5/x-1
AlexFokin [52]
The first step for solving this equation is to determine the defined range.
\frac{ x^{4}  }{x-1} = \frac{5}{x-1}, x ≠ 1
Remember that when the denominators of both fractions are the same,, you need to set the numerators equal. This will look like the following:
x^{4} = 5
Take the root of both sides of the equation and remember to use both positive and negative roots.
x +/- \sqrt[4]{5}
Separate the solutions.
x = \sqrt[4]{5}           , x ≠ 1
x = -\sqrt[4]{5} 
Check if the solution is in the defined range.
x = \sqrt[4]{5} 
x = -\sqrt[4]{5} 
This means that the final solution to your question are the following:
x = \sqrt[4]{5}          
x = -\sqrt[4]{5} 
Let me know if you have any further questions.
:)
7 0
3 years ago
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