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Dima020 [189]
3 years ago
14

Solve for x in the equation x squared + 11 x + StartFraction 121 Over 4 EndFraction = StartFraction 125 Over 4 EndFraction.

Mathematics
2 answers:
Solnce55 [7]3 years ago
8 0

Answer:

the answer is x=-11/2 +or- 5 (rooted)5/2

AKA D

Step-by-step explanation:

Ira Lisetskai [31]3 years ago
6 0

Answer:

Below

Step-by-step explanation:

● x^2 + 11x + 121/4 = 125/4

Substract 125/4 from both sides:

● x^2 + 11x + 121/4-125/4= 125/4 -125/4

● x^2 + 11x - (-4/4) = 0

● x^2 +11x -(-1) = 0

● x^2 + 11 x + 1 = 0

This is a quadratic equation so we will use the determinanant (b^2-4ac)

● a = 1

● b = 11

● c = 1

● b^2-4ac = 11^2-4*1*1 = 117

So this equation has two solutions:

● x = (-b -/+ √(b^2-4ac) ) / 2a

● x = (-11 -/+ √(117) ) / 2

● x = (-11 -/+ 3√(13))/ 2

● x = -0.91 or x = -10.9

Round to the nearest unit

● x = -1 or x = -11

The solutions are { -1,-11}

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Ab and bc form a right angle at point B. if a= (-3,-1) and B= (4,4) what is the equation of BC?
Vesnalui [34]

Answer:

Option C -7x-5y=-48

Step-by-step explanation:

step 1

Find the slope of AB

we have

A(-3,-1) and B(4,4)

The slope m is equal to

m=(4+1)/(4+3)

m=5/7

step 2

Find the slope of BC

we know that

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we have

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substitute

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step 3

Find the equation of the line into slope point form

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Multiply by 5 both sides

5y-20=-7x+28

7x+5y=28+20

7x+5y=48

Multiply by -1 both sides

-7x-5y=-48

3 0
3 years ago
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