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zheka24 [161]
3 years ago
8

Which fractions are equivalent to 10/12? Select each correct answer. ​ ​2/3​ ​5/6​ ​12/24​ ​30/36​ ​50/60​ ​60/84​

Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

[See Below]

Step-by-step explanation:

✦ Turn into decimals:

  • \frac{10}{12}=0.83
  • \frac{2}{3} =0.67
  • \frac{5}{6} =0.83
  • \frac{12}{24} =0.5
  • \frac{30}{36} =0.83
  • \frac{50}{60} =0.83
  • \frac{60}{84} =0.71

So \frac{10}{12} ≈ \frac{5}{6},\frac{30}{36},and,\frac{50}{60}.

~<em>Hope this helps Mate. If you need anything feel free to message me. </em>

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b. 50 degrees

Step-by-step explanation:

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3 years ago
Let f(x) = -4x + 7 and g(x) = 2x - 6. <br> Find (fºg)(1).<br><br> A 23<br> B 0<br> C 3<br> D -4
Anit [1.1K]

Answer:

I will get the function of g (x) and plug it on X in the function of f ( x ) and then later substitute X with 1

3 0
2 years ago
(1 + 2/3)*(1+2/5)*(1+2/7)*(1+2/9)
strojnjashka [21]

Answer:  11/3 or 3.6 or 3 2/3

Step-by-step explanation:

All you have to do is simplify the expression

7 0
3 years ago
If the quadratic formula is used to find the solution set of 3x2 + 4x - 2 = 0, what are the solutions?
7nadin3 [17]

Answer:

x=\frac{-2}{3} \pm \frac{\sqrt{10}}{3}

Step-by-step explanation:

Compare ax^2+bx+c to 3x^2+4x-2.

We have a=3,b=4,c=-2.

The quadratic formula is for solving equations of the form ax^2+bx+c=0 and is x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}.

So we are going to plug in our values in that formula to find our solutions,x.

If you want to notice it in parts you can.

Example I might break it into these parts and then put it in:

Part 1: Evaluate b^2-4ac

Part 2: Evaluate -b

Part 3: Evaluate 2a

------Let's do these parts.

Part 1: b^2-4ac=(4)^2-4(3)(-2)=16-12(-2)=16+24=40.

This part 1 is important in determining the kinds of solutions you have. It is called the discriminant.  If it is positive, you have two real solutions.  If it is negative, you have no real solutions (both of the solutions are complex).  If it is 0, you have one real solution.

Part 2: -b=-4 since b=4.

Part 3: 2a=2(3)=6.

Let's plug this in:

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

or in terms of our  parts:

x=\frac{\text{Part 2} \pm \sqrt{\text{Part 1}}}{\text{Part 3}}

x=\frac{-4 \pm \sqrt{40}}{6}

40 itself is not a perfect square but it does contain a factor that is.  That factor is 4.

So we are going to rewrite 40 as 4 \cdot 10.

x=\frac{-4 \pm \sqrt{4 \cdot 10}}{6}

x=\frac{-4 \pm \sqrt{4} \cdot \sqrt{10}}{6}

x=\frac{-4 \pm 2\cdot \sqrt{10}}{6}

I'm going to go ahead and separate the fraction like so:

x=\frac{-4}{6} \pm \frac{2 \cdot \sqrt{10}}{6}

Now I'm going to reduce both fractions:

x=\frac{-2}{3} \pm \frac{1 \cdot \sqrt{10}}{3}

x=\frac{-2}{3} \pm \frac{\sqrt{10}}{3}

6 0
3 years ago
Use numerals instead of words
Likurg_2 [28]

Answer:

Step-by-step explanation:

Put in the 3 and 4 so it is the square root of 3^4 - -6^2

The square root of 3^4 + 6^2

The square root of 3^4 is 3^2 so

9 + 6^2

=> 9 + 36

=> 45

45 in numerals is XLV

6 0
3 years ago
Read 2 more answers
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