Answer:
So, the first three nonzero terms in the Maclaurin series are:
Step-by-step explanation:
From exercise we have the next function y = 6 sec(3x).
We know that Maclaurin series for the function sec x, have the following form:
So, for the given function y = 6 sec(3x), we get:
So, the first three nonzero terms in the Maclaurin series are:
Answer: the correct answer is 20
Step-by-step explanation:
The formula for determining the distance between two points on a straight line is expressed as
Distance = √(x2 - x1)² + (y2 - y1)²
Where
x2 represents final value of x on the horizontal axis
x1 represents initial value of x on the horizontal axis.
y2 represents final value of y on the vertical axis.
y1 represents initial value of y on the vertical axis.
From the graph given,
x2 = - 7
x1 = 5
y2 = - 7
y1 = 9
Therefore,
Distance = √(- 7 - 5)² + (- 7 - 9)²
Distance = √(- 12²) + (- 16)²
= √(144 + 256) = √400
Distance = 20
10 is letter b. I hope this helps!!!
X = 47 + 9y
xy = 1860
y(47 + 9y) = 1860
47y + 9y² = 1860
9y² + 47y - 1860 = 0
> using a quadratic equation solver on a calculator but you can also use the quadratic equation = [-b+/- √(b²-4ac)]/(2a)
> only integer solution is x = 12
12y = 1860
y = 155
integers are 12 and 155
Answer:
Senior citizen ticket: $3
Student ticket: $9
Explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)
