h(t)=(t+3) 2 +5 h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plu
lesya692 [45]
Answer:
1
Step-by-step explanation:
If I understand the question right, G(t) = -((t-1)^2) + 5 and we want to solve for the average rate of change over the interval −4 ≤ t ≤ 5.
A function for the rate of change of G(t) is given by G'(t).
G'(t) = d/dt(-((t-1)^2) + 5). We solve this by using the chain rule.
d/dt(-((t-1)^2) + 5) = d/dt(-((t-1)^2)) + d/dt(5) = -2(t-1)*d/dt(t-`1) + 0 = (-2t + 2)*1 = -2t + 2
G'(t) = -2t + 2
This is a linear equation, and the average value of a linear equation f(x) over a range can be found by (f(min) + f(max))/2.
So the average value of G'(t) over −4 ≤ t ≤ 5 is given by ((-2(-4) + 2) + (-2(5) + 2))/2 = ((8 + 2) + (-10 + 2))/2 = (10 - 8)/2 = 2/2 = 1
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The equation of a circle is (x-h)^2+(y-k)^2=r^2, where (h,k) is the center and r is the radius.
To find the radius, we would find the square root of 144, which is 12.
r=12
:)
Answer:
Always
Step-by-step explanation:
Answer:
.
Step-by-step explanation:
We have been given a geometric sequence 18,12,8,16/3,.. We are asked to find the common ratio of given geometric sequence.
We can find common ratio of geometric sequence by dividing any number by its previous number in the sequence.
Let us use two consecutive numbers of our sequence in above formula.
will be 12 and 
will be 18 for our given sequence.
Dividing our numerator and denominator by 6 we will get,
Let us use numbers 8 and 16/3 in above formula.
Therefore, we get as common ratio of our given geometric sequence.
We write the expression:
((2 ^ (1/2)) * (2 ^ (3/4))) ^ 2
We use for this case the properties of lso exponents:
((2 ^ (1/2)) * (2 ^ (3/4))) ^ 2
((2 ^ (2/2)) * (2 ^ (6/4)))
((2 ^ (1)) * (2 ^ (3/2)))
((2 ^ (1 + 3/2))
((2 ^ (5/2))
answer:
((2 ^ (5/2))
option 2
