Answer: Eleventh Grade
Step-by-step
The ratio of tenth graders to the school's total population is 86:255 = 33.7%.
The ratio of eleventh graders to the school's total population is 18:51 = 35.3%.
Since the probability of a student being in either tenth, eleventh, or twelfth grade = 1 = 100% (that is, certainty), then the probability of a randomly drawn student being in twelfth grade is (100-33.7-35.3)% = 31.0%.
When randomly choosing one student from the whole school, it is most likely (35.3%) that the student is in the eleventh grade.
Answer:
All real numbers are solutions.
Step-by-step explanation:
Let's solve your equation step-by-step.
7x− 3 = − 3 + 7x
Step 1: Simplify both sides of the equation.
7x − 3 = −3 + 7x
7x + −3 = −3 + 7x
7x − 3 = 7x − 3
Step 2: Subtract 7x from both sides.
7x− 3 −7x = 7x −3 −7x
−3 = −3
Step 3: Add 3 to both sides.
−3 + 3 = −3 + 3
0 = 0
The solution of (3,13) means you need to create two lines that satisfy x = 3 and y = 13
The two lines can be anything as long as they give this solution
For example, if you wrote x + y = 16 (you know their values already)
Then write another y - x = 10
From here you have your equations, turn them into the f(x) form.
x + y = 16 can be turned into y = 16 - x which is f(x)=16-x
y-x = 10 can be turned into y = 10 + x which is g(x)=10 + x
Answer:
Step-by-step explanation:
Total red haired students = 15+5 = 20
Boys = 15
<u><em>Fraction:</em></u>
=> 
<u><em>In simplest form:</em></u>
=>
Answer:
The mass of the radioactive sample after 40 minutes is 12.8 g.
Step-by-step explanation:
The mass of the sample can be found by using the exponential decay equation:
Where:
N(t): is the amount of the sample at time t =?
N₀: is the initial quantity of the sample = 120 g
t = 40 min
λ: is the decay constant = 0.056 min⁻¹
Hence, the mass of the sample after 40 min is:
Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.
I hope it helps you!
