Given:
Eighteen 2.5 gallon buckets are needed to fill a cistern with water.
To find:
The constant of variation.
Solution:
If y is directly proportional to x, then
Where, k is constant of variation.
In the given problem, water in cistern (w) is directly proportional to number of buckets (n).
(Capacity of each bucket is 2.5 gallons)
Therefore, the constant of variation is 2.5.
Answer:
The missing frequencies are x = 8 and y = 43.
Step-by-step explanation:
Median Value =70
Then the median Class =60-80
Let the missing frequencies be x and y.
Given: Total Frequncy = 200 , Median = 46
From the table
Here, n = 200
n/2 = 100
Lower Class Boundary of the median class, l=60
Frequency of the median class(f) =66
Cumulative Frequency before the median class, f=42+x
Class Width, h=10
200=149+x+y
200=149+8+y
y=200-(149+8)
y=43
Hence, the missing frequencies are x = 8 and y = 43.