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ddd [48]
2 years ago
11

Which situation shows a constant rate of change.

Mathematics
2 answers:
krek1111 [17]2 years ago
7 0
D is the answer hope this helped
lana [24]2 years ago
3 0

D because it is the only one that is unpredictable

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Alicia had - $11.00 in her
lana [24]

Answer:

$42

Step-by-step explanation:

It's $42 because 11+44.50 is 54.50 and then you take out 6.25 twice because it's her and one friend to get 42 dollars. Hope this helps!

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2 years ago
Which is the best estimate of the difference between
Romashka-Z-Leto [24]

Answer:

c. 5

Step-by-step explanation:

678 rounds to 700 and 218 rounds to 200. 700-200=500

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Need help ASAP please
OlgaM077 [116]

Step-by-step explanation:

sue = 18 sweets

tony= 18 sweets

(sue)      S= (18 - x)-5

(tony)     T=(18 + x) ÷ 2

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6 0
2 years ago
Figure A is a scale image of Figure B, as shown.
Inessa [10]

9514 1404 393

Answer:

  x = 2

Step-by-step explanation:

Using the scale factor, we have ...

  x/8 = 0.25/1

  x = 8(0.25) . . . . multiply by 8

  x = 2

_____

<em>Additional comment</em>

I like to write proportions with the variable in the numerator. That way they are easily solved by a single multiplication. The trick is to get corresponding parts in the same positions. Here, the fractions are written ...

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5 0
3 years ago
Before a bag of flour can be sold, it must be 40 kilograms but can be within 0.5
Serjik [45]

Answer:

The minimum acceptable weight of the flour bag is 39.5 kg,

and its maximum acceptable weight is 40.5 kg

Step-by-step explanation:

Notice that the selling weight of the bag to be sold (x) needs to differ from 40 kg at most 0.5 kg. Therefore, we can write the following inequality:

|x-40|\leq 0.5

The inequality can be solve once we remove the absolute value symbol, and solve for the unknown "x". Recall that in order to solve it, we need to consider the two possible cases:

a) that the expression within the absolute value symbol is larger than or equal to zero, and b) that the expression is less than zero.

a) If x-40\geq 0 then its absolute value is equal to itself (x-40), and when we remove the absolute value symbols, we get:

x-40\leq 0.5\\x\leq 0.5+40\\x\leq 40.5\,\,kg

which means that the weigh "x" of the flour bag should be smaller or equal than 40.5  kg

b) If x-40, then the absolute value of this is its opposite : -x+40, and the inequality becomes:

-x+40\leq 0.5\\40\leq 0.5+x\\40-0.5\leq x\\39.5\leq x

which means that the weight of the flour bag must be larger than or equal to 39.5 kg

So, the minimum acceptable weight of the flour bag is 39.5 kg, and the maximum acceptable weight is 40.5 kg

6 0
3 years ago
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