Amount of water in the pool at the end of the day is 5457798.7 gallons
<u>Explanation:</u>
Given:
Initial amount of water in the pool = 45,000 gallons
Increase in amount = 0.75 in per minute
Time, t = 1 day
t = 24 X 60 min
t = 1440 min
So,
Increase in amount of water in 1 day = 0.75 in X 1440
= 1080 in
Volume of 1080 in of water = (1080 in)³
Volume from cubic inch to gallon = 5453298.7 gallon
Amount of water in the pool at the end of the day = 45000 + 5453298.7 gallon
= 5457798.7 gallon
Answer:
The lowest score a college graduate must be 577.75 or greater to qualify for a responsible position and lie in the upper 6%.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 500
Standard Deviation, σ = 50
We are given that the distribution of test score is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.06.
P(X > x) = 6% = 0.06
Calculation the value from standard normal z table, we have,

Hence, the lowest score a college graduate must be 577.75 or greater to qualify for a responsible position and lie in the upper 6%.
22 = z + (-9) Switch the sides
z = 22 - (-9) Solve
z = 31 So, z = 31
Answer:
13
Step-by-step explanation:
3 x 3 = 9
7 + 3 = 10
7 + ? = 3 + 7 + 3 + 7
7 + ? = 20
? = 13
Answer A and Answer D along with the ones you picked beforehand