All categories

3 years ago

Write four different equations that have –3 as the solution.

Mathematics

2 answers:

vodomira [7]3 years ago

8 0

1 + -4

2 + -5

3 + -6

4 + -7

Scorpion4ik [409]3 years ago

8 0

5 + -8

6 + -9

7 + -10

8 + -11

You might be interested in

A cylinder soup has a radius of 1,6 in and is 5/7 in. tall what is the volume

nata0808 [166]

Answer:

$V=0.0623\ inch^3$

Step-by-step explanation:

Given that,

The radius of cylinder, r = 1/6 inch

The height of the cylinder, h = 5/7 inch

We need to find the volume of the cylinder. The formula for the volume of a cylinder is given by :

$V=\pi r^2 h\\\\=3.14\times (\dfrac{1}{6})^2\times \dfrac{5}{7}\\\\V=0.0623\ inch^3$

So, the volume of the cylinder is equal to $0.0623\ inch^3$ .

6 0

3 years ago

There are 1,023 M&M's in a bag. Out of 1,023 M&M's, 132 M&M's are blue, 69 are green, 68 are brown, 63 are olive, 62

lesantik [10]

The probability that the person pulls 1 blue M&M given that one is only allowed to pull 5 random M&M's per day will be 0.6450.

<h3>How to calculate probability?</h3>

From the information given, there are 1,023 M&M's in a bag and out of 1,023 M&M's, 132 M&M's are blue.

Therefore, the probability of getting a blue M&M will be:

= 132/1023

= 0.1290

Therefore, since the person is given the chance to pull 5 random M&M's per day, the probability will be:

= 0.1290 × 5

= 0.6450

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

4 0

2 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

3 years ago

In kilometers, the approximate distance to the earth's horizon from a point h meters above the surface can be determined by eval

Maslowich

In kilometers, the approximate distance to the earth's horizon from a point h meters above the surface can be determined by evaluating the expression

$d= \sqrt{12h}$

We are given the height h of a person from surface of sea level to be 350 m and we are to find the the distance to horizon d. Using the value in above expression we get:

$d= \sqrt{12*350}=64.81$

Therefore, the approximate distance to the horizon for the person will be 64.81 km

8 0

3 years ago

4) A zoologist was checking the weights of three gorillas. Gorilla A weighed 559 pounds, gorilla B weighed 827 pounds and gorill

miss Akunina [59]

Answer:

1,516 pounds

Step-by-step explanation:

Gorilla A weighed = 559 pounds Gorilla B weighed = 827 pounds Gorilla C weighed = 130 pounds

Total weight of the gorillas = gorilla A + gorilla B + gorilla C

= 559 pounds + 827 pounds + 130 pounds

= 1,516 pounds

Total weight of the gorillas = 1,516 pounds

6 0

3 years ago