What is the average rate of change of f(x)=x²+4x+4 from x=1 to x=3?

Mathematics

1 answer:

Liula [17]2 years ago

4 0

Answer:

F(3) - F(1) / (3-1)

(3^2 + 3*4 + 4) - (1^2 + 1*4 + 4) / (2)

(9+12+4) - (1+4+4) / (2)

(25)-(9)/(2)

(16)/(2)

Step-by-step explanation:

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Jerry bought 6.95 pounds of cherry and lime jelly beans dor his birthday party. If 1.75 pounds were cheery, how many pounds were

Gekata [30.6K]

So you have 6.95 pounds and 1.75 pounds of it is cherry.

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3 years ago

In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study

astra-53 [7]

Answer:

C. z = 2.05

Step-by-step explanation:

We have to calculate the test statistic for a test for the diference between proportions.

The sample 1 (year 1995), of size n1=4276 has a proportion of p1=0.384.

$p_1=X_1/n_1=1642/4276=0.384$

The sample 2 (year 2010), of size n2=3908 has a proportion of p2=0.3621.

$p_2=X_2/n_2=1415/3908=0.3621$

The difference between proportions is (p1-p2)=0.0219.

$p_d=p_1-p_2=0.384-0.3621=0.0219$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{1642+1415}{4276+3908}=\dfrac{3057}{8184}=0.3735$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3735*0.6265}{4276}+\dfrac{0.3735*0.6265}{3908}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00006}=\sqrt{0.00011}=0.0107$