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Lady_Fox [76]
3 years ago
14

Find the area of the trapezoid

Mathematics
2 answers:
bija089 [108]3 years ago
4 0

Answer:

Please the attached file for the answer. I hope that helps

kompoz [17]3 years ago
4 0
It’s 40.5 :))) hope this helps
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The area of a rectangular table top is 24 ft.² the length of the table is 2 feet longer than its width which equation could be u
Goryan [66]

Answer: D) 24 = w^2 + 2w

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a rectangle (A) = length (L) x width (w)

Since:

Length = w+2

Substituting: L =w+2 in the formula:

A = (w+2) w

Replacing with the value given:

24 = (w+2)w

Applying distributive property:

24 = w^2 + 2w

Feel free to ask for more if needed or if you did not understand something.

4 0
3 years ago
Ana has 31 1/2 cups of oat in a container. She used 4 1/2 of oats to make a loaf of bread. How much oats does Ana have left in t
WINSTONCH [101]

Answer:

b

Step-by-step explanation:

Take 1/2 off of the 31 1/12 to make it easier. That gives you 31 and 4. Then take one away from both numbers to get to 30 and 3. 30 minus 3 is 27.

5 0
2 years ago
182,886 rounded to the nearest tenth
sp2606 [1]
The answer is 182,886.0. If you were to round it to the nearest tenth, think about it. 182,886.00 rounded to the nearest tenth is what? So the answer is <span>182,886.0.
Hope that helped you.</span>
4 0
3 years ago
Read 2 more answers
Calculate the distance between the points J=(-3, 2) and K=(2, -2) in the coordinate plane.
Pavlova-9 [17]

Answer:

\sqrt{41}

Step-by-step explanation:

Hello!

In order to answer this question, we need to use the distance formula.

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The order of these points can be chosen in any way, but they need to be done in the same pair (just like when you find the slope).

For this problem, let's let the J pair be the x_2, y_2 pair and the K pair be the x_1,y_1 pair.

x_2 = -3

x_1 = 2

y_2 = 2

y_1 = -2

Now, let's plug these points in.

\sqrt{(-3-2)^2+(2-(-2))^2}

\sqrt{(-3-2)^2+(2+2)^2}

\sqrt{(-5)^2+(4)^2}

\sqrt{25+16}

\sqrt{41}

Thus, the distance between points (-3,2) and (2,-2) is \sqrt{41}.  

4 0
3 years ago
If you have a cat what is it name
AVprozaik [17]
Mine is Sea queen what is yours
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3 years ago
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