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2 years ago

PLZ HELP I WLL GIVE BRAINLIEST

2 answers:

6 0

The answer is B. Since it is flipping over the why y axis the y coordinate stays the same so in 3,5 the 5 is the y coordinate so it stays the same and the x coordinate changes to the opposite. So since 3 is the x coordinate it would change from 3 to -3 so it would be -3,5. The same goes for the -2,-4. The -4 stays the same since it is the y coordinate and the x coordinate changes from -2 to 2 so it become 2,-4. So it is b

EleoNora [17]2 years ago

5 0

Answer:

I believe that the answer is A

Step-by-step explanation:

Because when an image is reflected it's supposed to be prime. Also you just flip the coordinates and you have your coordinates.

Can you please mark me Brainliest??

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Math write the number shown by the blocks

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2 years ago

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The label on a large bag of flour states that it has 2 times as many cups of flour as a small bag. Casey measures 16 cups of flo

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2 years ago

“Calculate the lengths of the 2 unlabeled sides”

Tpy6a [65]

Answer:

NL = 4.33

NM = 5

Step-by-step explanation:

tan 60° = NL/2.5

tan 60° = 1.7321

so:

1.7321 = NL/2.5

NL = (2.5)(1.7321)

NL = 4.33

cos 60° = 2.5/NM

cos 60° = 0.5

so:

0.5 = 2.5.NM

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2 years ago

A 50 foot rope weighing a total of 32 lbs extended over a cliff that is 35 feet to the ground. A large 8 pound bucket with 19 ga

larisa86 [58]

Answer:

A function that gives the work required in foot-lbs to lift the bucket up x feet from the ground is $W=16(50-x)+(19-\frac{x}{5})(8.3)x$ and the work to get the bucket to the top of the cliff is 3726 foot-lbs

Step-by-step explanation:

Work done to lift the rope by distance x feet:

$W_1=32(\frac{50-x}{2})$

Work done to lift the bucket by distance x feet:

$W_2=(19-\frac{x}{5})(8.3)x$

On reaching top 7 gallons of water spilled out so , on going up by x feet $\frac{7x}{35}=\frac{x}{5}$ gallons of water spilled out.

a function that gives the work required in foot-lbs to lift the bucket up x feet from the ground:

$W=16(50-x)+(19-\frac{x}{5})(8.3)x$

Now the work to get the bucket to the top of the cliff i.e. x =35

$W=16(50-35)+(19-\frac{35}{5})(8.3)(35)$

W=3726

Hence, a function that gives the work required in foot-lbs to lift the bucket up x feet from the ground is $W=16(50-x)+(19-\frac{x}{5})(8.3)x$ and the work to get the bucket to the top of the cliff is 3726 foot-lbs

5 0

2 years ago

Please answer this today

bazaltina [42]

4.16667 yd.
288 in.
2.5 miles
hope this helps!

6 0

2 years ago

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