An organism’s genotype describes the allele combination for a trait . Answer A is the correct answer
1. The percent probability that the first child of the couple will have Huntington's disease is 50%
2. The percent probability that four of the seven children will have Huntington's disease is 6.25%
<h3>Genetical probabilities</h3>
The disease is autosomal dominant. Only one dominant allele is needed for the disease to be manifested.
The husband is Hh and the wife is hh.
Hh x hh
Hh Hh hh hh
Hh (affected) = 1/2
hh (unaffected) = 1/2
1. Probability that the first child of this couple will have Huntington's disease is the same as the probability of having the disease. Thus, it is 1/2 (50%)
2. Probability that four of the seven children will have Huntington's disease is the same as the probability of having the disease in 4 places.
1/2 x 1/2 x 1/2 x 1/2 = 1/16 or 6.25%
More on genetic probabilities can be found here: brainly.com/question/13764507
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Nitrification. Hope this helped!
The answer to the given question above would be the second option. Based on the given scenario above, the reason why the new rodent with the nearby rodents and gets viable but infertile offspring is that the <span>new rodents probably derive from fairly recent ancestors that experienced dispersive allopatric speciation. Hope this helps.</span>
The esophagus has a simple but significant functions to animals who has it. These functions can be a) to swallow food and serve as a passageway to the stomach and b) may serve to release the eaten food that might have some harmful compositions or chemicals -the vomit response.
