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mote1985 [20]
4 years ago
9

$3500 at 10% for 2 years

Mathematics
1 answer:
nignag [31]4 years ago
4 0
The amount paid is $11,900.

First, you multiply $3,500 and 0.1 (10%). This gives you $350, which you multiply by 24 (24 months or 2 years), giving you $8,400. Finally, you add $8,400 and $3,500 to get your final answer.

I hope this helps!
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Evaluate 3 to the 2nd power plus 7 times 2
Olin [163]

Hey there!

3^2 + 7 • 2

3^2 = 3 • 3 = 9

9 + 7 • 2

7 • 2 = 14

9 + 14 = 23

Answer: 23 ☑️

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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(35x+18)=126. I think this is right not for sure
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Hatah and his 3 friends are each running an equal part of a la mile race.
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Answer:3.5 miles

Step-by-step explanation:

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4 years ago
There are six houses in a colony, such that 3 houses are in one row and the other 3 houses are in the opposite row. The three ho
Reil [10]

The GREEN house is diagonally opposite the orange-coloured house.

There are six houses in a colony, such that 3 houses are in one row and the other 3 houses are in the opposite row.

Each house is painted with a different colour from red blue, green,

yellow, pink and orange.

1. Houses at the corner are not painted in blue and red colour

2. House painted orange colour is not opposite the house painted in green colour

3. Yellow and pink coloured houses are not in the same row

We need to find which house is diagonally opposite the orange-coloured house

<h3>What is probability?</h3>

Probability can be defined as the ratio of the number of favourable outcomes to the total number of outcomes of an event. For an experiment having 'n' number of outcomes, the number of favourable outcomes can be denoted by x. The formula to calculate the probability of an event is as follows.

Probability(Event) = Favorable Outcomes/Total Outcomes = x/n

Arrangement is

Row1              1             2             3

Row2             4             5             6

Houses at the corner are not painted blue and red colour

1, 3, 4 & 6 are at the corner hence 2 and 5 has been Blue and Red in colour.

Blue = B , Red = R

Row1              1             B/R             3

Row2             4            R/B             6

House painted with orange colour is not opposite the house painted with green colour

Yellow and pink coloured houses are not in the same row

Also yellow and pink can not be opposite as then orange will be opposite to green

Hence yellow and pink are diagonally opposite

Hence green house is opposite to orange House

Row1              Y/P             B/R                G/O

Row2             O/G            R/B                 P/Y

or

Row1              O/G             B/R               P/Y  

Row2             Y/P            R/B                 G/O

The GREEN house is diagonally opposite the orange-coloured house.

To learn more about probability visit:

brainly.com/question/9793303.

#SPJ4

4 0
1 year ago
What number must you add to complete the square?<br> x^2 + 2x = -1
Andru [333]
\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}


If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248


\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}

6 0
3 years ago
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