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Olenka [21]
2 years ago
15

Simplify the expression please help me with this I need help now plz and thank you

Mathematics
2 answers:
Tema [17]2 years ago
7 0

Answer:

68

Step-by-step explanation:

4 + (11 - 3)^2

= 4 + 8^2

= 4 + 64

= 68

e-lub [12.9K]2 years ago
4 0

Answer:

It is like this first we should subtract

then square and addition

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Can someone help me with this
slega [8]

Answer:

4π

Step-by-step explanation:

This is a sinusoidal function.

The period of the function is basically the length from one wave crest to the next crest. We can take any 2 subsequent crests.

Lets take our first crest to be at 3π

The next one will be at 7π, as we can see

So, the length from one crest to the next is the period, which is:

7π - 3π

= 4π

Third answer choice is right, 4π is the period.

8 0
3 years ago
A town's population has been growing linearly. In 2003 the population was 47,000. The population has been growing by 1200 people
blsea [12.9K]

Answer:

Step-by-step explanation:

The population in 2003= 47000

Since the population increase by 1200 every year,

in 2004 the population will be 47000+1200

in 2005 the population will be 47000+(1200+1200) which is the same as

47000+2(1200) where 2 is 2 years after 2003,

Therefore the population x years after 2003 is 47000+x(1200).

P= 47000+1200x

b) The population at 2009 which is 6 years after 2003 will be

47000+(1200)*6=47000+7200= 54200

The population at 2009 is 54200,

7 0
3 years ago
What is the weight on earth of a girl with a mass of 44 kg?
Alexus [3.1K]
431.2 is the answer to your question
3 0
3 years ago
Can any one help me 11 points no lnks pls. Just help with any of these
zvonat [6]

Answer:

5. m<1 = 114 degrees

   m<2 = 66 degrees

6. 2x + 3x + 4x = 9x = 180, x = 20

7. 3

8. 1/3

<em>Hope that helps!</em>

<em>-scsb</em>

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
2 years ago
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