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elena55 [62]
3 years ago
9

Consider the graph with four lines below. On a coordinate plane, line a has a positive slope and goes through points (negative 1

, 0) and (1, 2), line b has a negative slope and goes through (negative 2, 2) and (negative 1, negative 1), line c has a negative slope and goes through (0, 3) and (1, 0), and line d is horizontal at y = 1. By inspection, which system would have no solution? line a and line b line a and line c line b and line c line b and line d

Mathematics
1 answer:
yan [13]3 years ago
5 0

Answer:

The correct option is;

line a and line b

Step-by-step explanation:

Lina a passes through (-1, 0) and (1, 2)

Line b passes through (2, 2) and (-1, -1)

Line c passes through (0, 3) and (1, 0)

Line d passes through y = 1

An equation that has no solution

By examination, from the plot of the coordinates using an online tool, the system that would have no solution is the system of line a and line b because they are parallel lines and cannot meet or have a point where there is a common solution, therefore, there are no solutions when the equations of the two lines are combined in one equation

Slope of line a = -2/-2 = 1

Slope of line b = 3/3 = 1

The slopes of lines a and b are equal, therefore, line a and line b are parallel.

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Answer:

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Step-by-step explanation:

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kvv77 [185]

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c but you have it so thanks

Step-by-step explanation:

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