The answers to the question is -33
Answer: 2 54
Step-by-step explanation:
c = number of children tickets sold
a = number of adult tickets sold.
we know that 178 total tickets were sold, thus whatever "c" and "a" are, c + a = 178.
the price of a child ticket is $5.4, so the price for all "c" tickets must be 5.4c.
the price of a adult ticket is $9, so the price for all "a" tickets must be ac.
we also know the total sales for all tickets combined is $1310.4, so then 5.4c + 9a = 1310.4.
![\bf \begin{cases} c+a=178\implies \boxed{c}=178-c\\ 5.4c+9a=1310.4\\[-0.5em] \hrulefill\\ 5.4c+9\left( \boxed{178-c} \right)=1310.4 \end{cases} \\\\\\ 5.4c+1602-9c=1310.4\implies -3.6c+1602=1310.4\implies -3.6c=-291.6 \\\\\\ c=\cfrac{-291.6}{3.6}\implies c=81](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20c%2Ba%3D178%5Cimplies%20%5Cboxed%7Bc%7D%3D178-c%5C%5C%205.4c%2B9a%3D1310.4%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%205.4c%2B9%5Cleft%28%20%5Cboxed%7B178-c%7D%20%5Cright%29%3D1310.4%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%205.4c%2B1602-9c%3D1310.4%5Cimplies%20-3.6c%2B1602%3D1310.4%5Cimplies%20-3.6c%3D-291.6%20%5C%5C%5C%5C%5C%5C%20c%3D%5Ccfrac%7B-291.6%7D%7B3.6%7D%5Cimplies%20c%3D81)