Answer:
The number is 91
Step-by-step explanation:
Let x be the ones place digit and y be the tens place digit,
Then the number would be 10y + x,
We have,
y - x = 8
Possible values of y and x = { (8, 0), (9, 1) }
∵ 0 is not the digit of the number,
Hence, y = 9 and x = 1
Therefore, required number = 10(9) + 1 = 90 + 1 = 91
First: 0
Second: 0
Third: -5
Fourth: y=4x
1) (-4) + (-9) = -13
2) 5 + (-12) = -7
3) -6 + 5 = -1
4) -7 + 7 = 0
<span>5) -7 + 2 ___ 3 + (-9)
- 5 ____ - 6
</span>-7 + 2 > 3 + (-9)
6) <span>4 + (-8) ___ 6 + (-8) + (-6)
- 4 ____ - 8
</span><span>4 + (-8) > 6 + (-8) + (-6)
7) </span><span>$66
8) </span><span>-$12
</span>
Answer:
5!*4! is equivalent to 5*(4!)^2
Step-by-step explanation:
5!*4! = 2880
5*(4!)^2 = 2880
Answer:
-17x-3
Step-by-step explanation:
Distribute the negative to the second part of the equation. remove the parenthesis from the first part and then add like values.
-4x-2-13x-1
-4x-13x-2-1
-17x-3