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Xelga [282]
3 years ago
13

Is y = 0(x-4)2 + 3 a quadratic function? Explain?​

Mathematics
1 answer:
Misha Larkins [42]3 years ago
5 0

Answer:

No

Step-by-step explanation:

I hope the picture helps

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You start with the equation 12b=24 . What step should you take to find the quantity that equals 4b?
ch4aika [34]

Answer:

divide each side by 3

Step-by-step explanation:

12÷3=4 and 24÷4= 6 the value of 4b=6

8 0
3 years ago
What is the answer to 2/3a-7=-3
MrRa [10]

Answer:

a = 6

Step-by-step explanation:

\frac{2}{3} a - 7 = -3\\\frac{2}{3} a = 4\\2a = 12\\a = 6

4 0
4 years ago
What is the general form of the equation for the given circle? A. x2 + y2 − 8x − 8y + 23 = 0 B. x2 + y2 − 8x − 8y + 32 = 0 C. x2
raketka [301]

Answer:

The correct option is A....

Step-by-step explanation:

Look at the attached picture:

A=(4,7)

B=(7,4)

The standard form of circle equation is:

(x-h)^2 +(y-k)^2 = r^2

Here h and k is the centre which is (4,4)

radius = 7-4 = 3

Now use the formula to find the answer:

(x-h)^2 +(y-k)^2 = r^2

(x - 4)^2 + (y - 4)^2 = 3^2

If we expand the formula we get:

x^2 - 8x + 16 + y^2 - 8y + 16 = 9

x^2 - 8x + y^2 - 8y + 23 = 0

Thus the correct option is A....

8 0
3 years ago
Determine the next step for solving the quadratic equation by completing the square.
nexus9112 [7]

\qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

the idea behind the completion of the square is simply using a perfect square trinomial,  hmmm usually we do that by using our very good friend Mr Zero, 0.

if we look at the 2nd step, we have a group as x² - x, hmmm so we need a third element, which will be squared.

keeping in mind that the middle term of the perfect square trinomial is simply the product of the roots of "a" and "b",  so in this case the middle term is "-x", and the 1st term is x², so we can say that

\stackrel{middle~term}{2(\sqrt{x^2})(\sqrt{b^2})~}~ = ~~\stackrel{middle~term}{-x}\implies 2xb~~ = ~~~~ = ~~-x \\\\\\ b=\cfrac{-x}{2x} \implies b=-\cfrac{1}{2}

so that means that our missing third term for a perfect square trinomial is simply 1/2, now we'll go to our good friend Mr Zero, if we add (1/2)², we have to also subtract (1/2)², because all we're really doing is borrowing from Zero, so we'll be including then +(1/2)² and -(1/2)², keeping in mind that 1/4 - 1/4 = 0, so let's do that.

-3~~ = ~~-2\left[ x^2-x+\left( \cfrac{1}{2} \right)^2 ~~ - ~~\left( \cfrac{1}{2} \right)^2\right]\implies -3=-2\left(x^2-x+\cfrac{1}{4}-\cfrac{1}{4} \right) \\\\\\ -3=-2\left(x^2-x+\cfrac{1}{4} \right)+(-2)-\cfrac{1}{4}\implies -3=-2\left(x^2-x+\cfrac{1}{4} \right)+\cfrac{1}{2} \\\\\\ -3-\cfrac{1}{2}=-2\left(x^2-x+\cfrac{1}{4} \right)\implies -\cfrac{7}{2}=-2\left(x-\cfrac{1}{2} \right)^2\implies \cfrac{7}{4}=\left(x-\cfrac{1}{2} \right)^2

~\dotfill\\\\ \pm\sqrt{\cfrac{7}{4}}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}+\cfrac{1}{2}=x \implies \cfrac{\pm\sqrt{7}+1}{2}=x

8 0
2 years ago
Which is shown, an altitude, a median, or neither?
Pani-rosa [81]
Altitude is shown
Hope this helps :)
6 0
4 years ago
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