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11Alexandr11 [23.1K]
3 years ago
8

Find the value of x round the length to the nearest tenth. The diagram is not drawn to scale.

Mathematics
2 answers:
Sidana [21]3 years ago
7 0

Answer:

x=2890.1m

Step-by-step explanation:

From the given figure, it can be seen that AD is parallel to BC, therefore using the alternate angles property, we have

∠DAC=∠BCA=10°

Also, the measure of AB is 500m.

Now, using trigonometry, we have

sin10^{\circ}=\frac{AB}{AC}

Substituting the given values, we have

0.173=\frac{500}{x}

x=\frac{500}{0.173}

x=2890.1m

Therefore, the value of x is 2890.2 meters.

Anna35 [415]3 years ago
5 0

Answer:

80

Step-by-step explanation:

has to be 180

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What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps. put the answer in units²
AlladinOne [14]

Answer:

Therefore the Area of Rhombus ABCD is 36 unit².

Step-by-step explanation:

Given:

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l(AC) = \sqrt{((-1-(-1))^{2}+(-6-0)^{2} )}=\sqrt{36}\\l(AC)=6\ unit

Similarly for BD we have,

l(BD) = \sqrt{((5-(-7))^{2}+(-3-(-3))^{2} )}=\sqrt{144}\\l(BD)=12\ unit

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\textrm{Area of Rhombus}=\dfrac{1}{2}\times AC\times BD

\textrm{Area of Rhombus}=\dfrac{1}{2}\times 6\times 12=36\ unit^{2}

Therefore the Area of Rhombus ABCD is 36 unit².

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