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Anna [14]
3 years ago
14

(6x 7)(6x-7) determine each product

Mathematics
1 answer:
Luden [163]3 years ago
6 0
36x - 42x +42x -49
simplified to
36x -49
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42 forty 2 over negitive 7<br> ___<br> -7
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What is the question ????
i do not understand what the question is

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4 years ago
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How do I do algebra?
Zielflug [23.3K]
You multiply and add like terms, depending on the equation that you have
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3 years ago
An account pays 6% compound interest. In year 1, the amount in the account is $70. How much is in the account in year 5?
kobusy [5.1K]

Answer:

$91 is the answer.

Step-by-step explanation:

R = 6%

P = $70

T = 5 year

now

I = PTR/100

=(70×5×6)100

= 2100/100

= $21

So,

I = A-P

21 = A-70

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8 0
3 years ago
What value(s) of x will make x^2=25 true
lora16 [44]

Answer:

5 and up

Step-by-step explanation:

5^2=25

thus

25=25

5 0
3 years ago
Suppose a basketball player is practicing shooting, and has a prob-ability .95 of making each of his shots. Also assume that his
Karo-lina-s [1.5K]

Answer:

0.082

Step-by-step explanation:

Number of attempts = n = 100

Since there are only two outcomes and in-dependent of each other, the probability of missing a shot  = 1 - Probability of making each shot

p = 1 - 0.95 = 0.05

Possion Ratio (λ) = np where n is the number of events and p is the probability of the shot missing

λ = 100 x 0.05 = 5

Define X such that X = Number of misses and X ≅ Poisson (λ = 5)

P [X ≤ 2] = P [X = 0] + P [X = 1] + P [X = 2]

P [X ≤ 2] = e⁻⁵ + e⁻⁵ x 5 + e⁻⁵ x 5²/2!

P [X ≤ 2] = e⁻⁵ [1 + 5 + 5²/2!]

P [X ≤ 2] = e⁻⁵ x 12.25 = 0.082

The required probability that there are at most 2 misses in the first 100 attempts is 0.082

7 0
3 years ago
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