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3 years ago

7

WHATS THE ANSWER ILL GIVE BRAINLIEST.

1 answer:

Gemiola [76]3 years ago

8 0

A I’m pretty sure!!!

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A rectangular jewelry box costs $125 to gold plate. Calculate the cost of gold plating a box which is similar in shape and that

Alja [10]

To determine the amount of gold plating necessary for the similar box, you will use the fact that it is 8 times larger in volume to determine how many times larger the area is. This would be what you will multiply $125 by.

Volume is a three dimensional measurement, so the fact that it is 8 times larger tells us each dimension was 2 times larger (2 x 2 x 2=8).

Area is a two dimensional measurement, so the area would have been 2 x 2 or 4 times larger. This means the price would be 4 times as much.
$125 x 4 = $500.

It will cost $500 to gold plate the similar jewelry box.

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Chuge%7B%5Cunderline%7B%5Cfrak%7B%5Cred%7BQ%7D%5Cgreen%7Bu%7D%5Cpink%7Be%7D%5Corange%7Bs%7D%

balu736 [363]

<u>Given </u><u>:</u><u>-</u>

x/2 = 3

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

The value of 2x + 2 .

<u>Solution</u><u> </u><u>:</u><u>-</u>

The given equation to us is ,

$\longrightarrow$ x/2= 3

$\longrightarrow$ x = 3*2

$\longrightarrow$ x = 6

Now we need to find out ,

$\longrightarrow$ 2x + 2

$\longrightarrow$ 2(6) + 2

$\longrightarrow$ 12 + 2

$\longrightarrow$ 14

<u>Hence </u><u>the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>1</u><u>4</u><u>.</u>

7 0

2 years ago

Read 2 more answers

Evaluate this expression by distributing the multiplication over division: 5 x (7+4)

Maru [420]

Answer:

I think you can write like this:

5 x (5+2+4)

OR

5 x 11

Step-by-step explanation:

My own knowladge

Hope it helps

Put a thanks

Thank you

6 0

3 years ago

I NEED HELP PLEASE, THANK YOU!

bixtya [17]

Answer:

$\sqrt{37}$

Step-by-step explanation:

To find the distance between a point (m, n ) and the line

Ax + By + C = 0

d = $\frac{|Am +Bn+C|}{\sqrt{A^2+B^2} }$

Here (m, n) = (6, 2) and rearranging the line

6x - y + 3 = 0 ← in general form

with A = 6, B = - 1 and C = 3 , then

d = $\frac{|6(6)-1(2)+3|}{\sqrt{6^2+(-1)^2} }$

= $\frac{|36-2+3|}{\sqrt{36+1} }$

= $\frac{37}{\sqrt{37} }$

Rationalise the denominator by multiplying numerator/ denominator by $\sqrt{37}$

= $\frac{37}{\sqrt{37} }$ × $\frac{\sqrt{37} }{\sqrt{37} }$

= $\frac{37\sqrt{37} }{37}$ ← cancel 37 on numerator/ denominator

= $\sqrt{37}$

5 0

3 years ago

Read 2 more answers

Help! I need some help...

AURORKA [14]

The complement is 38
and the supplement is 128

8 0

3 years ago

Read 2 more answers