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Verizon [17]
3 years ago
5

What number is 33% of 1,000

Mathematics
1 answer:
horsena [70]3 years ago
4 0
The correct answer is 330.
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Pleasee mwa mwa mwa help me
sammy [17]

Answer: About (-2.414, 0) and (0.414, 0)

Step-by-step explanation:

       Let us graph the equation given and see what the x-intercepts are. These are points where the line intercepts the x-axis. <em>See attached</em>.

       This means our x-intercepts are at about (-2.414, 0) and (0.414, 0).

                        These are also equal to -1-\sqrt{2} and  -1+\sqrt{2}

8 0
2 years ago
Read 2 more answers
7x+5y=-13<br> -2x=7y+26<br> Solve by elimination
RSB [31]

Answer:

Point form : (1,-4)

Equation for, : x=1, y=-4

Step-by-step explanation: Add the fractions in order to solve for the first variable. Plug this vale into the other equations in order to solve for the remaining variables.

Hope this helps you out! ☺

5 0
3 years ago
Read 2 more answers
a recipe requires 1/4 pound of potatoes to make 3 servings of soup Don has one and a half pound of potatoes how many servings ca
tamaranim1 [39]
18 servings of soup he can make with the potatoes!
8 0
3 years ago
.Joline collects hockey cards.
shusha [124]

Answer:

25 Cards

Step-by-step explanation:

If 5 cards is 20%  and  you only need 5 more then that means you have the other 80%. So you 20 80/20 which is 4. Then do 4x5=20 then add the 5 you still need.

3 0
3 years ago
Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2
34kurt
\displaystyle\iint_Rye^x\,\mathrm dA=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=5}r^2\sin\theta e^{r\cos\theta}\,\mathrm dr\,\mathrm d\theta

which follows from the usual change of coordinates via

\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}

and Jacobian determinant

|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|

Swap the order, so that the integral is

\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr

and now let \sigma=r\cos\theta, so that \mathrm d\sigma=-r\sin\theta. Now, you have

\displaystyle\int_{r=0}^{r=5}\int_{\sigma=0}^{\sigma=r}re^\sigma\,\mathrm d\sigma\,\mathrm dr=\int_{r=0}^{r=5}r(e^r-1)\,\mathrm dr=4e^5-\dfrac{23}2
7 0
3 years ago
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