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Advocard [28]
2 years ago
9

Use the periodic table to answer the questions below.

Chemistry
2 answers:
Yanka [14]2 years ago
7 0

Answer:

where is the diagram shown

ExtremeBDS [4]2 years ago
4 0

Answer: 1s2, 2s2, 2p3

Explanation: Nitrogen is an element number 7 on the periodic table which means that it has 7 proton. And for an atom to maintain its electrical neutrality, the number of proton is equal to the number of electron. That is, equal number of positively and negatively charge.

So, 7 electrons of Nitrogen is

1s2, 2s2, 2p4

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Please answer correctly ...I will mark you brainliest
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Answer:

Ali will need to either taste test or test the drinks on a ph scale. A neutral drink is water, as neutral has a ph of 7. The ph scale ranges from 1 to 14, going from acidic to basic. So if the drink has a ph less than 7, it is acidic, if its more, its basic.

4 0
3 years ago
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Which of the following is a primary cause of LO/TO accidents?
Marianna [84]
<h2>Answer:</h2>

The correct answer is

A) Regular operation

<h2>Explanation:</h2>

Even those workplaces that have established LO/TO processes face challenges, including: Lack of specific procedures written for each piece of equipment identifying all energy sources and energy isolation devices. Lack of comprehensive safety training for everyone in the workplace. Incorrect tag use.

So, regular operation is the primary cause of LO/TO accidents.

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2 years ago
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What volume of carbon dioxide gas at STP is required to produce 456.9g of lithium carbonate?
Margarita [4]

Answer:

It would have to be around 9.8 volume

Explanation:

7 0
3 years ago
Solid sodium iodide is slowly added to a solution that is 0.0050 M Pb 2+ and 0.0050 M Ag +. [K sp (PbI 2) = 1.4 × 10 –8; K sp (A
UkoKoshka [18]

Answer:

[Ag⁺] = 5.0x10⁻¹⁴M

Explanation:

The product solubility constant, Ksp, of the insoluble salts PbI₂ and AgI is defined as follows:

Ksp(PbI₂) = [Pb²⁺] [I⁻]² = 1.4x10⁻⁸

Ksp(AgI) = [Ag⁺] [I⁻] = 8.3x10⁻¹⁷

The PbI₂ <em>just begin to precipitate when the product  [Pb²⁺] [I⁻]² = 1.4x10⁻⁸</em>

<em />

As the initial [Pb²⁺] = 0.0050M:

[Pb²⁺] [I⁻]² = 1.4x10⁻⁸

[0.0050] [I⁻]² = 1.4x10⁻⁸

[I⁻]² = 1.4x10⁻⁸ / 0.0050

[I⁻]² = 2.8x10⁻⁶

<h3>[I⁻] = 1.67x10⁻³</h3><h3 />

So, as the [I⁻] concentration is also in the expression of Ksp of AgI and you know concentration in solution of I⁻ = 1.67x10⁻³M:

[Ag⁺] [I⁻] = 8.3x10⁻¹⁷

[Ag⁺] [1.67x10⁻³] = 8.3x10⁻¹⁷

<h3>[Ag⁺] = 5.0x10⁻¹⁴M</h3>

6 0
3 years ago
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