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3 years ago

Use the periodic table to answer the questions below.

Chemistry

2 answers:

Yanka [14]3 years ago

7 0

Answer:

where is the diagram shown

ExtremeBDS [4]3 years ago

4 0

Answer: 1s2, 2s2, 2p3

Explanation: Nitrogen is an element number 7 on the periodic table which means that it has 7 proton. And for an atom to maintain its electrical neutrality, the number of proton is equal to the number of electron. That is, equal number of positively and negatively charge.

So, 7 electrons of Nitrogen is

1s2, 2s2, 2p4

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Cylinder with a mass of 12g has a radius measuring 2cm and height of 6cm what is its density

lakkis [162]

Answer:

Given:

m = 12 g, the mass of the cylinder

r = 2 cm, the radius of the cylinder

h = 6 cm, the height of the cylinder.

Calculate the volume, V, of the cylinder.

V = πr²h

= π*(2 cm)²*(6 cm)

= 75.398 cm³

By definition,

density = mass/volume.

Therefore,

density = m/V

= (12 g)/(75.398 cm³)

= 0.159 g/cm³

= 0.16 g/cm³ (nearest hundredth)

Answer: 0.16 g/cm³

8 0

3 years ago

What charges must the particles have to create the electric field shown?

Law Incorporation [45]

Answer: B Explanation: The reason is u can’t have a stable current without a positive and negative.

6 0

2 years ago

Suppose that an element has two isotopes. The average atomic mass of the element is 45.737 u . One isotope has a mass of 40.149

Ugo [173]

Answer:

The answer to your question is 49.08 u

Explanation:

Data

Average atomic mass = 45.737 u

Isotope 1 = 40.149 u abundance = 37.46%

Isotope 2 = ?

Process

1.- Calculate the abundance of isotope 2

abundance isotope 1 + abundance isotope 2 = 100%

37.46 + abundance isotope 2 = 100

abundance isotope 2 = 100 - 37.46

abundance isotope 2 = 62.54

2.- Calculate the mass of isotope 2

Average atomic mass = (abundance x mass isotope 1) + (abundance x

mass isotope 2)

45.737 = (0.3746 x 40.149) + (62.54 x mass isotope 2)

mass isotope 2 = [45.737 - (0.3746 x 40.149)]/ 62.54

mass isotope 2 = [45.737 - 15.0398]/ 62.54

mass isotope 2 = 30.6972/62.54

mass isotope 2 = 0.4908 x 100

mass isotope 2 = 49.08 u

7 0

3 years ago

Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluor

jenyasd209 [6]

Answer:

27.9 g

Explanation:

CsF + XeF₆ → CsXeF₇

First we convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles, using its molar mass:

Molar mass of CsXeF₇ = 397.193 g/mol

73.1 g CsXeF₇ ÷ 397.193 g/mol = 0.184 mol CsXeF₇

As 1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.

Now we convert 0.184 moles of CsF to moles, using the molar mass of CsF:

Molar mass of CsF = 151.9 g/mol

0.184 mol * 151.9 g/mol = 27.9 g

4 0

3 years ago

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Lostsunrise [7]

If it is already balanced because the compounds aluminum(Al) and oxygen(O) have the same number of atoms

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3 years ago