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tatyana61 [14]
3 years ago
13

Ammonia gas combines with excess oxygen gas to produce nitric oxide and water. How many grams of ammonia gas would have to react

in order to release 154 kJ of energy
Chemistry
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

11.6g of NH₃(g) have to react

Explanation:

For the reaction:

4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g) ΔH = -905kJ

<em>4 moles of ammonia produce 905kJ</em>

Thus, if you want to produce 154kJ of energy you need:

154kJ × (4 mol NH₃ / 905kJ) = <em>0.681moles of NH₃. </em>In mass -Molar mass ammonia is 17.031g/mol-

0.681mol NH₃ × (17.031g / mol) = <em>11.6g of NH₃(g) have to react</em>

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What is the final concentration of a solution prepared by diluting 35.0 mL of 12.0 M HCl to a final volume of 1.20 L
sineoko [7]

Answer: The final concentration of a solution is 0.350 M

Explanation:

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = concentration of concentrated acid solution = 12.0 M

V_1 = volume of concentrated acid solution = 35.0 ml

C_2 = concentration of diluted acid solution= ?

V_2 = volume of another acid solution= 1.20 L = 1200 ml

( 1L=1000ml)

Putting in the values:

12.0\times 35.0=C_2\times 1200

C_2=0.350M

The final concentration of a solution prepared by diluting 35.0 mL of 12.0 M HCl to a final volume of 1.20 L is 0.350 M

8 0
3 years ago
Please please help me!​ please do what you can do and what you understand
ExtremeBDS [4]

Answer:

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Explanation:

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6 0
3 years ago
10. When a 13.6 g sample of a compound containing only magnesium and oxygen is decomposed, 5.4 g of oxygen is obtained. What is
irinina [24]

Answer:5.4 g / 13.6 g *100

Explanation:Its is the correct answer

7 0
4 years ago
Read 2 more answers
Lucite contains 59.9 g C, 8.06 g H,
Alexxandr [17]
You start by finding the mol of each

59.9g C x (mol C / 12.01 g C) = 4.98 mol C
8.06g H x (mol H / 1.00 g H) = 8.06 mol H
32.0 g O x (mol O / 16.0 g O) = 2 mol O

So when you set it up you have
C4.98 H8 O2

You divide each by the smallest mol. The smallest mol is 2

C2 H4 O2.5

However you can’t have half a mol in the empirical formula. If the value ends in 0.5, you multiply everything by 2

You’re left with

C2H8O5

The EMPIRICAL formula for lucite is C2H8O5

Note empirical is not the same as chemical formula.
6 0
2 years ago
A chemistry student needs 60.00 g of butanoic acid for an experiment. He has available 120. g of a 36.9% w/w solution of butanoi
Finger [1]

Answer:

No solution

Explanation:

36.9% w/w solution of butanoic acid in ethanol means 36.9 grams of butanoic acid per 100 grams of solution. The amount of butanoic acid in 120.0 g of the solution may be calculated:

(120.0 g solution)(36.9 g butanoic acid / 100 g solution) = 44.3 g butanoic acid.

There is not sufficient butanoic acid for the experiment.

6 0
3 years ago
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