Question

Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 21.321.3 and the temperature is 37.0°C37.0°C ? ΔG°′ΔG°′ for the reaction is −16.7 kJ/mol−16.7 kJ/mol .

Answer 1

Answer:

ΔG = -8.812 kJ/mol

Explanation:

To obtain the free energy of a reaction you can use the expression:

ΔG = ΔG° + RT ln Q

Where:

ΔG° is Standard Gibbs Free energy: -16.7kJ/mol = -16700J/mol

R is gas constant: 8.314472 J/molK

T is absolute temperature (37°C + 273.15 = 310.15K)

And Q is reaction quotient: 21.3

Replacing in the formula:

ΔG = ΔG° + RT ln Q

ΔG = -16700J/mol + 8.314472J/molK*310.15K ln 21.3

ΔG = -8812.4J/mol

ΔG = -8.812 kJ/mol