Answer:
hope you understand and your answer is correct
we need to get the total calories, we can get it by getting the average of calories of the protein, fat, and carbohydrates:
calories of protein = 15g x 4 KCal/g
= 60 KCal
calories of fat = 1 g x 9 KCal/g
= 9 kCal
calories of carbohydrates = 42 g x 4 KCal/g
= 168 Kcal
∴ the total calories = 60 + 9 + 168 = 237Kcal = 0.237 Cal
to get the resualt to two significant figures
∴ the resault is = 0.24 Cal = 240 KCal
The required amount of KClO₃ to prepare a saturated solution is 48 grams.
<h3>What is solubility?</h3>
The ability of a material, the solute, to create a solution with another substance, the solvent, is known as solubility.
Given graph is plotted between the temperature and solubility of the substance at 100g of water, so for the given points calculation will be:
- According to the graph for the KClO₃ we require almost 48g of KClO₃ to prepare a saturated solution.
- From the graph it is clear that at 40°C 40g of KCl will dissolve in 100g of water then amount of KCl which will dissolve in 68g of water will be calculated as:
x = (40)(68) / (100) = 27.2g
- On the basis of the graph, if 75 grams of calcium chloride is added to 100 g of water at 25°C then the obtained solution is the unsaturated as they have les solute then the limit.
- Based on the graph cerium sulfate behaves like a precipitate which will not dissolve at any temperature and present in the physical state.
- We can add more 30g to make the KCl solution saturated.
Hence, we require almost 48g of KClO₃ to prepare a saturated solution of KClO₃.
To know more about solubility, visit the below link:
brainly.com/question/16903071
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Answer:
Reason: Gravitational pull of the Moon
Explanation:
Weight of Garfield is 24 lbs on the Earth. He took a flight from the Earth to the Moon where the gravity is 1/6 of the gravity on the Earth.
But when reaches the Moon he found he weighed only 6 lbs. It is due to the gravitational pull of the Moon.
Mass of an object reamins the same at every location while its weight changes due to the change in acceleration due to gravity. It is equal (on Moon) to 1/6 the of acceleration due to gravity on the earth.
