Question

If the ultraviolet photon has a wavelength of 249 nm and one of the photons emitted by the fluorescent material has a wavelength of 425 nm, what is the wavelength of the other emitted photon? Assume that none of the energy of the absorbed ultraviolet photon is converted to other forms. Express your answer to three significant figures and include appropriate units.

Answer 1

Answer:

601 nm

Explanation:

Energy of photon having wavelength of λ nm

= $\frac{1244}{\lambda}$eV

Energy of 249 nm photon

=$\frac{1244}{249}$

=4.996 eV

Similarly energy of 425nm photon

=$\frac{1244}{425}$

=2.927 eV

Difference = 2.069 eV.

This energy will give rise to another photon whose wavelength will be

λ = $\frac{1244}{2.069}$

= 601 nm.