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il63 [147K]
3 years ago
9

The bottom of the dais jewelry box of the rectangle with length of 5 3/8 inch in width of 3 and 1/4 in what is the area of the b

ottom of the jewelry box
Mathematics
1 answer:
lesantik [10]3 years ago
7 0

Answer:The area of the bottom of the jewelry box is 139.75 inch^2

Step-by-step explanation:

The area of a rectangle is expressed as

Area = Length × width

The length of the rectangular bottom of dais jewelry box is 5 3/8 inch. Converting to improper fraction, it becomes 43/8 inch.

The width of the rectangular bottom of dais jewelry box is 3 1/4 inch. Converting to improper fraction, it becomes 13/4 inch.

The area of the bottom of the jewelry box will be

43/8 × 13/4 = 559/32 = 139.75

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2x + 3y = 7 3x + 2y = 8
Kipish [7]

Answer:

\boxed{\sf \ \ \ x=2, \ \ y =1 \ \ \ }

Step-by-step explanation:

Hello,

Pls post the full question next time so that we can make sure what is expected.

I assume that you want to solve for (x,y)

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2*(2)-3*(1) gives

2*3x + 2*2y - 3*2x - 3*3y = 2*8 - 3*7 = 16 - 21 = -5

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3 years ago
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2 years ago
How would you solve 3x=18
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Hi!

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