Answer: help woth what?
Step-by-step explanation:
Step-by-step explanation:
- First, the radical needs to be alone on one side of the equation, if there is - 4, - 3 next to it then you'll have to transfer it to the opposite side like that:
5. (y+7)^0.5 - 4=4
(y+7)^0.5=8......
- Second, you need to square the two sides of the equation :
5.((y+7)^0.5) ^2=8^2
Y+7=64
Y+7-7=64-7
Y=57
Note: if the radical's index is (2) then you'll square the two sides of the equation, but if the index is (3) you'll have to cube the two sides of the equation, "look at the exercises 9,10"
Using a graph tool
case 1)
2x-y=-13
y=x+9
the solution is the point (-4,5)
see the attached figure N 1
case 2)
y=3x-7
y=2x-5
the solution is the point (2,-1)
see the attached figure N 2
case 3)
3x+2y=10
6x-y=10
the solution is the point (2,2)
see the attached figure N 3
case 4)
y=6
x=-5
the solution is the point (-5,6)
see the attached figure N 4
case 5)
4x-3y=5
3x+2y=-9
the solution is the point (-1,-3)
case 6)
x+y=7
x-y=-1
the solution is the point (3,4)
the answer in the attached figure
A standard deck of playing cards consists of 52 playing cards.
1. Count the probability of drawing two aces from a standard deck without replacment.
Among 52 playing cards are 4 aces, then the probability to select first ace is 4/52=1/13. After picking out first ace, only 3 aces left and in total 51 playing cards left, then the probability to select second ace is 3/51=1/17. Use the product rule to find the probability to select two aces without replacement:

2. Count the probability of drawing two aces from a standard deck with replacment.
Among 52 playing cards are 4 aces, then the probability to select first ace is 4/52=1/13. After picking out first ace, this card was returned back into the deck and the probability to select second ace is 4/52=1/13 too. Use the product rule to find the probability to select two aces with replacement:

3. If events A and B are independent, then 
All these three steps show you that the first card was replaced and events are independent.