1. n-3^2
2. 7-(2/n)
3. n=35+(1/2*35)+14
4. (1/n^2)-(19*n)
Find the range of the following data set: 6,2,59,12,11,9,9,54,54,46,2,32,43,11
Mkey [24]
Range is simply just the boundary that a set of numbers pass. So you need to find the largest and smallest values. So that would be 2 and 59. Therefore the range would be 2-59
Answer:
Sally
Step-by-step explanation:
Because you may work 8-10 hours and make $16-20 instead of 10 for the day
A.) 1/3 - 3(2/7x) - (3)(4) No because - (3)(4) is -12
B.) 1/3 - 6/7x + 12 Yes
C.) -11 2/3 - 6/7x No because 37/3 is 12 1/3
D.) 12 1/3 - 6/7x Yes
E.) 1/3 - 6(1/7x - 2) = 1/3 - 6/7x + 12 Yes
F.) 1/3 + (-3)(2/7x) - (3)(4) No because - (3)(4) is -12
Your answer is B, D, and E
Answer:
Step-by-step explanation:
1- on Monday the number of tricycles: 51/3=17 or 48/3=16 ( can't be 50)
2-the algebraic equation is : t=w/3 ( t=tricycle, w: wheels)
3-On Wednesday: (b for bicycle and t=tricycle)
2b+3t=61
b+t=24 ⇒ b=24-t
solve by substitution:
2(24-t)+3t=61
48-2t+3t=61
t=61-48 ⇒ t=11
solve for b=24-t
b=24-11=13
<h2>
t=11, b=13</h2>
4)t: tricycles, b for bicycles, n for tandem
t+b+n=144 ( each has one handlebar)⇒ t=144-b-n
2t+2b+4n ( for the pedales)
3t+2b+2n=320 ( for wheels)
solve by matrix or substitution: substitute t in the equations:
2t+2b+4n =378
3t+2b+2n=320
2(144-b-n)+2b+4n=378 ⇒ 288-2b-2n+2b+4n=378
3(144-b-n)+2b+2n=320 ⇒432-3b-3n+2b+2n=320
<u> </u>
288-2b-2n+2b+4n=378
432-3b-3n+2b+2n=320
2n=378-288 ⇒ n=90/2=45
-b-n=320-432
-b-45=-112
-b=-112+45 ⇒ b=67
t=144-45-67= 32
<h2>
b=67 , tricycle= 32 tandom= 45</h2><h2>
( answers in bold )</h2>