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prohojiy [21]
2 years ago
10

What’s the correct answer for this?

Mathematics
2 answers:
nadezda [96]2 years ago
6 0

Answer:

206°

Step-by-step explanation:

<JLK = 360° -154 ° = 206°

Note : angle at a point is 360°.

forsale [732]2 years ago
5 0

Answer:

A 206 degrees

Step-by-step explanation:

circles have a total of 360 degrees

360-154 = 206

If this helps please consider giving me brainliest.

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Rewrite as an addition problem:<br> (5w +6u) - (4w - 3u)
stepladder [879]

Answer:

(5w+ 6u ) + (-4w +3u)

Step-by-step explanation:

(5w+ 6u ) + (-4w +3u)

this can be done by multiplying all in the second parentheses by -1.

6 0
2 years ago
A line has a slope of -2 and passes through the point (3, 1). What is the equation of this line in slope-intercept form?
Zepler [3.9K]
Question 7. y = -2x + 7. y = mx + b; m= slope (-2) (3, 1) resolve for y. you have : 1= -2 (3) + b; 1 = -6 + b; 1 + 6 = b; b = 7. 











6 0
3 years ago
Find the x- and y-intercepts of the graph of x+y=17x+y=17d
butalik [34]

Answer:

fbdjenfg,scsv

Step-by-step explanation:

jgfnhgfbfu generally

5 0
3 years ago
Which graphs below have a domain of all real numbers? Which have a range of all real numbers? Which are functions?
slava [35]

Answer:

Step-by-step explanation:

From the picture attached,

Graph (A)

Domain of the function : (-∞, ∞) or a set of real numbers

Range of the function : (-∞, ∞) or a set of real numbers

Graph (B),

Domain : (-∞, ∞) Or a set of real numbers

Range : (-∞, 6] Or x ≤ 6

Graph (C),

Domain : [-2, ∞) or x ≥ -2

Range : (-∞, ∞) Or a set of real numbers

Therefore, Graphs (A), (B) have the domain of all real numbers and Graph (C) has the range of all real numbers.

Since all the parabolas are not the functions,

Therefore, Graph (C) is not a function. Graphs (A) and (B) are the functions.

3 0
3 years ago
Beth is putting up a fence in her yard so her dog can play outside. She purchased 80 feet of fencing. If the fenced area is a re
mariarad [96]

Answer:

10 feet

Step-by-step explanation:

The formula for the Perimeter fo a rectangle

= P = 2L + 2W

Where:

L = Length

W = Width

From the question

P = 80 feet

W = 30 feet

Hence:

80 = 2L + 2(30)

80 - 2(30) = 2L

80 - 60 = 2L

20 = 2L

L = 20/2

L = 10 feet

Hence, the length of the fenced area = 10 feet

4 0
2 years ago
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