All u have to do is 20-1=19
The y intercept is 17. You can see it clearly in the equation.
You cannot add row 2 to column 3 because they have different dimensions. You can do any of the other operations, but the only one that makes any sort of sense is ...
Multiply row 2 by -1 and add it to row 3
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It makes no sense to multiply a row by zero. That makes the entire row zero and makes the matrix useless for finding any sort of solution.
You can switch columns, but that doesn't get you any closer to a solution here.
If I were trying to find a solution, I might
switch rows 1 and 2
multiply the new row 1 by -3 and add it to the new row 2
multiply the new row 1 by 2 and add it to row 3
This sequence of operations will make the first column [1 0 0], reducing the problem to 2×2 from 3×3.
Answer to Problem 1: 53
Answer to Problem 2: x ≥ 2
Answer:
Step-by-step explanation:
<u>Part A:</u>
Lets take the value of a=10
Thus a+1=b
10+1=11 , it means the value of b is 11
11>10 or b>a
Now take the value of a as -3
Therefore a+1=b
-3+1= -2
-2>-3 or b>a
The pair of values for a and b are: a=10 then the value of b would be 11;
And a=-3; then the value of b would be: -2.
<u>Part B:</u>
It is not possible to create a pair of values for a and be, in which the numerical relationship shown in the given conditional statement is false, therefore b>a if a+1=b....
