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2 years ago

Find the intercept(s) of the following equation. y = 2x^2-8

Mathematics

1 answer:

grin007 [14]2 years ago

5 0

X intercepts- (2,0) and (-2,0)
y intercept- (0,-8)

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Justo ayer fue el cumpleaños de Mauricio. Si a la edad e Mauricio, le sumo 13, al resultado le resto 10, luego al nuevo resultad

bezimeni [28]

Answer:

Mauricio nació en el año 2000.

Step-by-step explanation:

Supóngase que el cumpleaños se celebra en el año 2020, si $x$ es la edad actual de Mauricio, entonces la expresión matemática que traduce el enunciado del problema es:

$\frac{(x+13)-10}{23} +20 = 21$

Ahora, se desarrolla y se simplifica la ecuación:

$\frac{x+3}{23}+20 = 21$

$\frac{x+3}{23} = 1$

Se despeja $x$ :

$x +3 = 23$

$x = 20$

Mauricio tiene 20 años.

Ahora, el año de nacimiento de Mauricio es la sustracción de la edad de Mauricio del año actual:

$y = 2020-20$

$y = 2000$

Mauricio nació en el año 2000.

3 0

2 years ago

A monkey has a strict banana eating

daser333 [38]

Answer:
Any way the monkey eats minimum 12 banas on each day of 8 days amointing=12*8=96 bananas

Excess bananas eaten=112–96=16

Monkey eats 8 bananas more on sunny days

number of sunny days=16/8=2 days

Number of sunny days in these 8 days=2 days

8 0

1 year ago

In the year 2003, a company made $6.8 million in profit. For each consecutive year after that, their profit increased by 13%. Ho

LenKa [72]

Answer:

$7.7 million

Step-by-step explanation:

Given: $6.8 million profit made by company.

13% increase in profit every year.

Now, finding the company´s profit in the year of 2006.

As we know there is 13% increase in profit.

∴ Profit increase= $\frac{13}{100} \times 6.8= \$ 0.884$

Next adding company´s profit with increase in profit to get profit in the year 2006.

∴ $6.8+0.884= \$ 7.684$ ≅ $7.7

The company´s profit in the year 2006 is $7.7 million.

6 0

2 years ago

Use known facts to find 9x5

Charra [1.4K]

If your asking to multiply 9x5 then the anwser is 45.

7 0

2 years ago

There are 100 students at a college who have taken a course in calculus, 110 who have taken a course in discrete mathematics, an

vesna_86 [32]

Answer:

110 students

Step-by-step explanation:

The number of students who have only taken calculus is given by the number of students who have taken calculus minus the students who have taken both classes:

$C =100 -50\\C= 50\ students$

The number of students who have only taken discrete mathematics given by the number of students who have taken discrete mathematics minus the students who have taken both classes:

$D =110 -50\\C= 60\ students$

The number of students that have taken a course in either calculus or discrete mathematics is:

$E = C+D = 50+60\\E= 110\ students$

7 0

2 years ago