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3 years ago

Given g(x) = 3x + 8 , what is the value of g(− 4) ?

Mathematics

2 answers:

Stella [2.4K]3 years ago

6 0

Answer:

g(-4) = -4

Step-by-step explanation:

So we are given the function g(x) = 3x + 8 and we are asked to find g(-4). To find g(-4), we would have to plug in -4 for x in the equation for g(x).

g(-4) = 3(-4) + 8 = -12 + 8 = -4

So g(-4) = -4.

I hope you find my answer and explanation to be helpful. Happy studying.

amid [387]3 years ago

4 0

Answer:

- 4

Step-by-step explanation:

Step 1:

g ( x ) = 3x + 8 Function

Step 2:

g ( x ) = 3 ( - 4 ) + 8 Input x

Step 3:

g ( x ) = - 12 + 8 Multiply

Answer:

g ( x ) = - 4 Add

Hope This Helps :)

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3 years ago

Read 2 more answers

What is the oblique asymptote of the function f(x) x^2+x-2/x+1

Mamont248 [21]

$f(x)=\displaystyle\frac{x^2+x-2}{x+1}=\frac{x(x+1)-2}{x+1}=x-\frac{2}{x+1}
$

$\displaystyle\lim_{x\to\infty}\left\{f(x)-x \right\}=\lim_{x\to\infty}\frac{2}{x+1}=\lim_{x\to\infty}\frac{\displaystyle\frac{2}{x}}{1+\displaystyle\frac{1}{x}}
=0$

Consequently, the limit of $f(x)$ as x approaches infinity is $x$ .

In other words, $f(x)$ approaches the line y=x,

so oblique asymptote is y=x.

I'm Japanese, if you find some mistakes in my English, please let me know.