Answer:
a) K₀ = ½ m v₀²
, b) = ½ m ²
, c) U = M g H1
, d) U = 0
, e) K = ½ M v₀²
,
f) K = ½ M ²
Explanation:
a) the mass of the glider is m
kinetic energy is
K = ½ m v²
It's like the table and the floor are fixed, the relative speed does not changes
K₀ = ½ m v₀²
b) = ½ m ²
c) the hanging mass is M
In this case the mass that is hanging is on the table that is at a height H1 with respect to the floor, the initial potential energy is
U = M g H1
d) the hanging mass decreases in height until it reaches the floor, where its height is zero
U = 0
e) If we assume that the glider and the hanging mass are connected by a rope, it must be in tension at all times, so the speed of the glider and the mass are the same, since they carry the same acceleration
K = ½ M v₀²
F)
K = ½ M ²