measures angular displacement per unit time. Its units are therefore degrees (or radians) per second.
Answer:
Vf= 3.435 m/s
Explanation:
Given:
Initial velocity Vi =0 m/s (starting from Rest position)
θ = 37⁰
Distance S = 1 m
To find: Final Velocity Vf=?
fist we have to find the down slope net acceleration a = g sin θ
a= 9.81 sin 37⁰ = 5.9 m/s²
By 3rd equation of motion
2 a S= Vf² - Vi²
Vf = Square root ( 2 × 5.9 m/s² × 1 + 0 m/s)
Vf = Square root (11.8)
Vf= 3.435 m/s
Answer:
ω = B₀q/m
Explanation:
The centripetal force on the charge equal the magnetic force on the charge. (Since the trajectory is a circle). So, mrω² = B₀qv.
v = rω The speed of the charge and r = radius of path
mrω² = B₀qrω
ω = B₀q/m
The angular frequency ω = B₀q/m
This is possible due to inertia of motion. which is nothing but newton's first law.
according to this law , an object tries to retain its state of motion or rest unless acted upon by an external force.
consider an object placed on a paper, initially both the object and paper are at rest. to pull the paper , we apply force on the paper and paper gains velocity. but the object keeps its motion of rest and hence the paper can be removed without moving the object.
Answer:
t = 025 s
Explanation:
We know
weight, W = 4 pounds
spring constant, k = 2 lb/ft
Positive damping, β = 1
Therefore mass, m = W / g
m = 4 / 32
= 1 / 8 slug
From Newtons 2nd law
where x(t) is the displacement from the mean or equilibrium position. The equation can be written as
Substituting the values, the DE becomes
Now the equation is
and on solving the roots are
= 
= -4
Therefore the general solution is 
Now for initial condition x(0) = -1 ft
x'(0)= 8 ft/s
Now we can find the equation of motion becomes,
Therefore, the mass passes through the equilibrium when
x(t) = 0
= 0
-1+4t = 0
t = 
= 0.25 s
