The vectors addition permits locating the perfect result for the sum of the two vectors in option B). See attached and the vector is directed to the right and up.
Vector addition is the operation of adding or extra vectors together into a vector sum. The so-known as parallelogram regulation gives the rule for vector addition of or greater vectors. for two vectors and, the vector sum is received via placing them head to tail and drawing the vector from the loose tail to the unfastened head.
A vector is an amount or phenomenon that has impartial residences: importance and direction. The time period also denotes the mathematical or geometrical representation of the sort of quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.
Vectors are used in technological know-how to describe something that has a direction and a magnitude. they're commonly drawn as pointed arrows, the length of which represents the vector's importance
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Which vector is the sum of vectors à and b?
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Asteroid belt, a region of thousands of asteroids in orbit of the sun between
Mars and Jupiter
Answer:
Energy Ouput (Useful) / Total Energy Input = 4000 / 4800 = .833
E = 83% assuming 4800 is actually input to fan
Ohm's law states that the electrical current (I) flowing in an circuit is proportional to the voltage (V) and inversely proportional to the resistance (R). ... Similarly, increasing the resistance of the circuit will lower the current flow if the voltage is not changed..hope it helps out
Answer:
A) C = 4.425 10⁻¹³ F, B) Q = 6.31 10⁻¹¹ C, C) E = 8.9 10⁴ N / C,
D) u_{E} = 3.19 10⁻⁹ J
Explanation:
Part A. Capacitance is
C = ε₀ A / d
in this case distance is d = 0.800 cm = 0.800 10⁻² m and the area of the plates is x = 0.200 cm= 0.2 10⁻² m, all the quantities must be in the SI system for the result to be in Farads
A = x²
A = (0.2 10⁻²)²
A = 4 10⁻⁶ m
let's calculate
C = 8.85 10⁻¹² 4 10⁻⁶ / 0.8 10⁻²
C = 44.25 10⁻¹⁴ F
C = 4.425 10⁻¹³ F
Part B. The charge on each plate is
Q = C ΔV
Q = 4.425 10⁻¹³ 120
Q = 6.31 10⁻¹¹ C
Part C. the electric field of a plate is
E = σ / 2ε₀
where the charge density is
σ = Q / A
we substitute
E =
let's calculate
E = 
E = 8.9 10⁴ N / C
Part D. stored energy
= ½ C V²
u_{E} = ½ 4.425 10⁻¹³ 120²
u_{E} = 3.19 10⁻⁹ J
