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ch4aika [34]
3 years ago
8

Please help me! -3a+6(1+6a)=4(8a+1)

Mathematics
1 answer:
den301095 [7]3 years ago
3 0

Answer:

-3a + 6 + 36a = 32a + 4

a = - 2

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I need help on this problem!!
Svetllana [295]
3.98*10^{6}(people)*\frac{1 mi^{2}}{1000 people} = 3.98*10^{6}* \frac{1 mi^{2}}{10^{3}} = 3.98*10^{6-3} mi^{2}=

=3.98*10^{3} mi^{2}
4 0
2 years ago
How do you simplify this?????
kap26 [50]
You have to break up 384 into numbers that can be taken out to the radical.

You can break up 384 into 2^3*2^3*6.

Since two 2’s can be taken you would have 4 on the outside and a 6 and x^4 left on the inside.

x^3 can be taken out, leaving an x inside the radical.

The final answer would be 4x on the outside and 6x left under the cubed radical

5 0
3 years ago
Help needed!! Don’t know how to do!!
Aleks [24]

Answer:

D,0,2,-2

Step-by-step explanation:

2x^5-3x^3-20x=0

x(2x^4-3x^2-20)=0

x=0

or 2x^4-3x^2-20=0

put x²=t

2t²-3t-20=0

-20×2=-40

8-5=3

8×-5=-40

2t²-(8-5)t-20=0

2t²-8t+5t-20=0

2t(t-4)+5(t-4)=0

(t-4)(2t+5)=0

t=4

x²=4

x=2,-2

t=-5/2

x²=-5/2

it gives imaginary  root. so real rational roots are 0,2,-2

3 0
3 years ago
Read 2 more answers
Simplify the complex fraction: ((3x-7)/x^2)/(x^2/2)+(2/x)
Archy [21]
Simplify the complex fraction: ((3x-7)/x^2)/(x^2/2)+(2/x)

\dfrac{ \dfrac{3x-7}{x^2} }{ \dfrac{x^2}{2} } + \dfrac{2}{x} =\qquad \qquad x \neq 0\qquad x^4 \neq 0 \\  \\  \\  \dfrac{(3x-7)*2}{x^2*x^2}+ \dfrac{2}{x} =  \\  \\  \\   \dfrac{6x-14}{x^4}+ \dfrac{2}{x} =\\  \\  \\  \dfrac{ 6x-14 }{ x^4 }+ \dfrac{2(x^3)}{x(x^3)}=\\  \\  \\  \boxed{  \dfrac{ 6x-14 +2x^3}{ x^4 } }

6 0
3 years ago
Find SP where MP=Rs875 and discount =Rs75
liraira [26]

Answer:

SP is Rs 800.

Step-by-step explanation:

MP = Rs 875

Discount = Rs 75

so

SP = MP - discount

= Rs 875 - Rs 75

= Rs 800

4 0
2 years ago
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