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ch4aika [34]
3 years ago
8

Please help me! -3a+6(1+6a)=4(8a+1)

Mathematics
1 answer:
den301095 [7]3 years ago
3 0

Answer:

-3a + 6 + 36a = 32a + 4

a = - 2

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3⁵.2⁴.2¹.3⁶.(3²)⁴ and down (2³)².3⁶​<br>​
BARSIC [14]

Answer:

\dfrac{3^{13}}{2}

Step-by-step explanation:

Given expression:

\dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot (3^2)^4}{(2^3)^2 \cdot 3^6}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies \dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot 3^8}{2^6 \cdot 3^6}

\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:

\implies \dfrac{3^{(5+6+8)} \cdot 2^{(4+1)}}{2^6 \cdot 3^6}

\implies \dfrac{3^{19} \cdot 2^{5}}{2^6 \cdot 3^6}

\implies \dfrac{3^{19} \cdot 2^{5}}{3^6 \cdot 2^6}

\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:

\implies 3^{(19-6)} \cdot 2^{(5-6)}

\implies 3^{13} \cdot 2^{-1}

\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}:

\implies \dfrac{3^{13}}{2^1}

\textsf{Apply exponent rule} \quad a^1=a:

\implies \dfrac{3^{13}}{2}

4 0
2 years ago
(u^2+9u+2)+(2u^3+5u^2+8)
Olenka [21]

Answer:

2 u ^3+ 6 u ^2 + 9 u + 10

Step-by-step explanation:

6 0
3 years ago
Joe has created a budget and has allocated $250 per month for food. at the end of the month he finds that he actually spent $340
Lilit [14]
So he is over budget by $90 and he needs to allocate his bills to allow for it

5 0
3 years ago
Find the slop-intercept form of the line whose slope is 5 and that passes through the point (-6,7).
Korvikt [17]
You know that the slope, m=5. You have a point (6,7) as (x,y). The slope-intercept form is y=mx+b. Plug in the number for x,y, and m, and then you would be able to find b using the slope-intercept form. Then rewrite the equation as y=5x+b, which you just found b.
(Here's the first step. 7=5(-6)+b). Find b, and then write the slope-intercept form as y=5x+b. 
3 0
3 years ago
What is the value of the expression “two less than six times the difference of a number and five” when n = 9?
Finger [1]

Answer:

Try solving 6(n-5)-2.

Step-by-step explanation:

I believe this can be set up as 6(n-5)-2. The difference of a number and five can be represented by n-5. If this needs to be multiplied by 6 (hence 6 times), it would become 6(n-5). Two less than that is represented by -2. Thus, two less than six times the difference of a number and five is 6(n-5) -2, which, when n=9 is plugged in, looks like 6(9-5) -2. Follow PEMDAS from there.

7 0
3 years ago
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